Question

我有一个这样的响应字符串：

|||COVID HPI^^^FEVER^^^Low Grade
|||COVID HPI^^^FEVER^^^Continuous
|||COVID HPI^^^RHINORRHEA/SNEEZING^^^No
|||GENERAL EXAM^^^CL^^^Conscious
|||GENERAL EXAM^^^ORIENTED^^^Yes

我想将其转换为如下形式：

{
  "COVID HPI": [
    {
      "FEVER": "Low Grade, Continuous",
      "RHINORRHEA/SNEEZING": "Yes"
    }
  ],
  "GENERAL EXAM": [
    {
      "CL": "Conscious",
      "ORIENTED": "Yes"
    }
  ]
}

没有丑陋的代码，我将无法超越：

const na = [];
    fetch('http://localhost/test/json/newdata.json')
    .then(response => {
       let vv = response.json();
       return vv;
    })
    .then(function(data){
    console.log(data[0]['tRxVal'])
        let nav = data[0]['tRxVal'].slice(3).split('|||');
        let nbv = nav.map(function(item,i){
            return item.split('^^^');
        });
        //console.log(nbv);
        nbv.forEach(function(v,i){
            if(!na.includes(v[0])){
                na.push(v[0]);
            }
        })
        console.log(na)

    })
    .catch(err => {
        // handle errors
    });

有人可以帮我吗谢谢

Answer 1

您应该尝试使用split函数。您可以先对"|||"的字符串进行拆分，然后再对"^^^"的所有结果字符串进行拆分，以便可以拆分键和值。

类似的东西（将其作为伪代码）

let strings = data.split("|||");
for (string in strings){
  let objectKeyValue = string.split("^^^");
  let object = objectKeyValue[0];
  let key = objectKeyValue[1];
  let value = objectKeyValue[2];
}

从这里开始，构成您的对象，您就很好了。

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split

Answer 2

以|||分隔以获取每一行，然后以^^^分隔每一行。然后，您可以这样思考每个“行”：<topLevelCategory>^^^<subCategory>^^^<subCategoryAnswer>。使用每一行的这种思维模型来构建对象。

const string = `|||COVID HPI^^^FEVER^^^Low Grade
|||COVID HPI^^^FEVER^^^Continuous
|||COVID HPI^^^RHINORRHEA/SNEEZING^^^No
|||GENERAL EXAM^^^CL^^^Conscious
|||GENERAL EXAM^^^ORIENTED^^^Yes`;

function stringToObj(str) {
  const branches = str.split('|||');
  const obj = {};
  branches.forEach((branch) => {
    const leaves = branch.split('^^^');
    const [top, sub, answer] = leaves;
    if (top) {
      if (!obj[top]) obj[top] = {};
      const trimmedAnswer = answer.trim();
      const curr = obj[top][sub];
      if (curr) {
        obj[top][sub] = `${curr}, ${trimmedAnswer}`;
      } else {
        obj[top][sub] = answer.trim();
      }
    }
  });

  return obj;
} 

console.log(stringToObj(string));

JavaScript如何将字符串转换为嵌套对象

2 个答案: