Question

我有这个脚本

#!/bin/bash
function labels2 () {
    awk '
    /[0-9]/{
    print substr($3,length($3)-11), $3
    }' $@ | /bin/sort -u  | awk '{print "BUILD: " NR, $2}'
}

function labels () {
    awk '
    /[0-9]/{
    BL[$3] = substr($3,length($3)-11)
    }
    END {
    asort(BL)
    for (i in BL) {
        print i, BL[i]
    }
    }' $@
}


labels $@
exit 0

for a in $@
do
    labels $@ | gawk '
    /BUILD:/ {
    BUILD[$2] = $3
    BUILDCNT ++
    next
    }
    /[0-9]/ {
    DATEd[$3] = $1
    TIMEd[$3] = $2
    MODULESd[$3] = $4
    CASESd[$3] = $5
    FAILEDd[$3] = $6
    COVERd[$3] = $7
    LOCd[$3] = $8
    }
    END {
    SUBSYSTEM=substr(FILENAME, 1, length(FILENAME)-7)
    LABEL= "\"" toupper(SUBSYSTEM) "\""
    print "{"
        print "subsystem: " LABEL ","
        print "    date: {"
        print "        label: " LABEL ","
        print "        data: ["
        for (i = 0 ; i <= BUILDCNT; i ++ ) {
            B=BUILD[i]
            if (DATEd[B]) { print "            [" i ", \"" DATEd[B] "\"]," }
        }
        print "        ]"
        print "    },"
    }
    ' - $a
done

此文本输入文件cos.txt

2011-01-22 22:12 P16A22_110114072915 22 1312 75 13.55 1399
2011-01-22 22:12 P16A22_110114072915 22 1312 75 13.55 1399

现在我的问题是，为什么打印出来

1 110114072915
2 110114072915

而不是

{ 
subsystem: "COS",
  date: {
        label: "CAS",
        data: [[1,"110114072915"],[2,110114072915]]
}

修改------------------------------------------- -------------------------------------

我按照你们的说法做了，但它部分奏效了。但现在它来自表格

1 110114072915
2 110114072965{
subsystem: "COS",
    date: {
        label: "COS",
        data: [
            [0, "3"],
        ]
    },

而不是表格

{ 
subsystem: "COS",
  date: {
        label: "CAS",
        data: [[1,"110114072915"],[2,110114072915]]
}

我该怎么改变？我也想这样做，他们按顺序

数组中的

=）

再次感谢您的帮助=）

Answer 1

因为

labels $@
exit 0      <-- you told exit after the function "labels"... ;)

这个脚本在哪里出错了

1 个答案: