Python 将 2D numpy 数组附加到 3D

时间:2020-12-26 16:40:10

标签: python arrays numpy

我遇到了对 numpy 数组的理解问题。 我有一个读取时看起来像这样的数据集:

[
   [ F0, F1, F2, F3 ... F22],
   [ G0, G1, G2, G3 ... G22],
   [ H0, H1, H2, H3 ... H22],
   [ I0, I1, I2, I3 ... I22],
   [ J0, J1, J2, J3 ... J22]
]

我想将它们转换成“三个一包”:

[
   [
      [ F0, F1, F2, F3 ... F22],
      [ G0, G1, G2, G3 ... G22],
      [ H0, H1, H2, H3 ... H22]
   ],
   [
      [ G0, G1, G2, G3 ... G22],
      [ H0, H1, H2, H3 ... H22],
      [ I0, I1, I2, I3 ... I22]
   ]
   ...
]

到目前为止,我已经编写了这段代码:

data = loadtxt('./training_data/set_0.csv', delimiter=';')
batch_size=3
features=17
labels=6

trainX = np.empty((0,batch_size, features), float)
for i in range(0, len(data)-batch_size):
    row_X = data[i:i+batch_size,0:features]
    trainX = np.append(trainX, row_X)

print(trainX[0])

记录 row_X 的形状就像我想要的那样给我 (3,17)。 但是 trainX 变量似乎包含这些数组的平面组合,我原以为 trainX[0] 的形状为 (batch_size,features)

1 个答案:

答案 0 :(得分:1)

import numpy as np

batch_size = 3


l = np.array([
   [1,2,3,4,5],
   [ 2,3,4,5,6],
   [ 3,4,5,6,7],
   [ 4,5,6,7,8],
   [ 5,6,7,8,9],
    [6,7,8,9,0],
])

output = [l[n:n+batch_size] for n in range(len(l)-batch_size+1)]

输出

[array([[1, 2, 3, 4, 5],
        [2, 3, 4, 5, 6],
        [3, 4, 5, 6, 7]]),
 array([[2, 3, 4, 5, 6],
        [3, 4, 5, 6, 7],
        [4, 5, 6, 7, 8]]),
 array([[3, 4, 5, 6, 7],
        [4, 5, 6, 7, 8],
        [5, 6, 7, 8, 9]]),
 array([[4, 5, 6, 7, 8],
        [5, 6, 7, 8, 9],
        [6, 7, 8, 9, 0]])]
相关问题