Question

我正在从 Excel 工作表获取输入，但日期不是可以操作的正确 ISO 格式，即该列如下所示，我正在尝试使用 javascript 日期和时刻将其转换为正确日期对其进行排序但是我没有得到正确的输出，我可以在这个问题上使用第二种意见。

输入["28/02/23","31/12/21","31/05/21","30/09/23","31/10/22","30/09/21","30/06/23","31/05/22","30/04/21","31/07/21","30/06/21","28/02/22","31/12/22","30/06/22","31/08/21","30/04/22","31/10/20","31/08/22","31/07/22","31/05/23","31/01/23","30/04/23","30/09/22","28/02/21","30/11/20","30/11/21","31/01/21","31/03/23","31/01/22","31/07/23","31/12/20","31/03/21","31/08/23","30/11/22","31/10/21","31/03/22","30/09/20"]

我写的方法

dateCompare = (d1, d2) => {
  let d1Component = d1.toString().split('/')
    , d2Component = d2.toString().split('/')
    , rD1 = new Date(parseInt(20 + d1Component[2]), d1Component[1] - 1, d1Component[0])
    , rD2 = new Date(parseInt(20 + d2Component[2]), d2Component[1] - 1, d2Component[0])
  return moment(rD1).isAfter(moment(rD2))
}

我从上述方法得到的输出是 ["30/09/35", "28/02/23", "31/05/21", "31/12/21", "31/10/22", "30/09/21", "30/09/20", "31/05/22", "30/04/21", "31/07/21", "30/06/21", "28/02/22", "31/12/22", "30/06/22", "31/08/21", "30/04/22", "31/10/20", "31/08/22", "31/07/22", "31/03/22", "31/01/23", "31/10/21", "30/09/22", "28/02/21", "30/11/20", "30/11/21", "31/01/21", "30/11/22", "31/01/22", "31/03/21", "31/12/20", "31/01/37", "31/07/23", "31/03/23", "30/04/23", "31/05/23", "30/06/23", "30/04/37", "31/10/23", "31/08/23", "30/09/23", "30/06/37", "29/02/24", "30/11/23", "31/12/23", "31/01/24", "31/08/37", "31/07/24", "31/03/24", "30/04/24", "31/05/24", "30/06/24", "30/11/37", "31/01/25", "31/08/24", "30/09/24", "31/10/24", "30/11/24", "31/12/24", "31/03/38", "31/08/25", "28/02/25", "31/03/25", "30/04/25"]，我认为它根本没有以任何方式排序。

Answer 1

比较函数应该返回负数表示小于，正数表示大于，0 表示等于，而不是 true/false。此外，由于您已经在使用 moment，因此也可以使用它来解析日期：

function dateCompare(d1, d2) {
    const d1Parsed = moment(d1, "DD/MM/YY");
    const d2Parsed = moment(d2, "DD/MM/YY");
    if (d1Parsed.isBefore(d2Parsed)) {
        return -1;
    } else if (d1Parsed.isSame(d2Parsed)) {
        return 0;
    } else {
        return 1;
    }
}

或者，取它们的时间戳的差（如果 d1Parsed 在 d2Parsed 之前，那么它的时间戳会更小，所以产生的减法将为负，如果它们相等，它将是 0 ，如果它更大，那就是正数，与之前的代码做同样的事情）：

function dateCompare(d1, d2) {
    const d1Parsed = moment(d1, "DD/MM/YY");
    const d2Parsed = moment(d2, "DD/MM/YY");
    return d1Parsed.valueOf() - d2Parsed.valueOf();
}

Answer 2

您可以使用地图并转换日期，而不是对它们进行排序。

const dates = ["28/02/23", "31/12/21", "31/05/21", "30/09/23", "31/10/22", "30/09/21", "30/06/23", "31/05/22", "30/04/21", "31/07/21", "30/06/21", "28/02/22", "31/12/22", "30/06/22", "31/08/21", "30/04/22", "31/10/20", "31/08/22", "31/07/22", "31/05/23", "31/01/23", "30/04/23", "30/09/22", "28/02/21", "30/11/20", "30/11/21", "31/01/21", "31/03/23", "31/01/22", "31/07/23", "31/12/20", "31/03/21", "31/08/23", "30/11/22", "31/10/21", "31/03/22", "30/09/20"];

const convertedDates = dates.map(d => {
  var day = d.split("/")[0];
  var month = d.split("/")[1];
  var year = d.split("/")[2];

  return "20" + year + '-' + ("0" + month).slice(-2) + '-' + ("0" + day).slice(-2);
})
.sort();
;

console.log(convertedDates);

Answer 3

不使用第三方库，您可以将 custorm 日期转换为符合 ISO 8601 的日期字符串并使用 String#localeCompare。

const
    getISO = string => string.replace(/(\d\d)\/(\d\d)\/(\d\d)/, '20$3-$2-$1'),
    data = ["28/02/23", "31/12/21", "31/05/21", "30/09/23", "31/10/22", "30/09/21", "30/06/23", "31/05/22", "30/04/21", "31/07/21", "30/06/21", "28/02/22", "31/12/22", "30/06/22", "31/08/21", "30/04/22", "31/10/20", "31/08/22", "31/07/22", "31/05/23", "31/01/23", "30/04/23", "30/09/22", "28/02/21", "30/11/20", "30/11/21", "31/01/21", "31/03/23", "31/01/22", "31/07/23", "31/12/20", "31/03/21", "31/08/23", "30/11/22", "31/10/21", "31/03/22", "30/09/20"];

data.sort((a, b) => getISO(a).localeCompare(getISO(b)));

console.log(data);

对格式不正确的日期进行排序

3 个答案: