Question

假设我们有一个List<Product>，列表中的每个产品都有很多List<Type>

public class Product{
public int Id {get:set;}
public string Name {get:set;}
public List<Type> Types {get;set;}
}

public class Type{
public int Id {get;set;}
public string Name{get;set;}
}

创建产品列表后，我需要按类型对它们进行分组，然后找到属于每种类型的所有内容。我想我应该尝试LINQ。这是我到目前为止所做的，但似乎不是完成工作的正确方法。可能有人可以帮助我。

var productsList = new List<Product>();
//Adding products and types for each of them

var productTypesList = new Dictionary<int, string>();

 foreach (var p in productsList)
                            {
                                var pTypes = p.Types;
                                foreach (var ptype in
                                    pTypes.Where(x=> !productTypesList .ContainsKey(x.Id)))
                                {
                                    productTypesList.Add(ptype.Id, ptype.Name);
                                }
                            }

然后我试图像这样搜索

foreach (var t in productTypesList)
{
var matches = productsList.FindAll(........); 
// from here I need to find all the product which belongs to type (t.id)

if (matches.Count > 0)
{
//Do somthing here
}
}

Answer 1

以下是您想要的：

var productsPerType =
    from t in products.SelectMany(
        p => p.Types, (p, t) => new { Product = p, TypeId = t.Id })
    group t by t.TypeId
    into g
    select new { g.Key, Products = g.Select(x => x.Product) };

首先，您执行SelectMany以获取产品内所有类型的列表。对于每种类型，您都会记住类型ID和相应的产品：

from t in products.SelectMany(
    p => p.Types, (p, t) => new { Product = p, TypeId = t.Id })

每个t现在都是一个包含类型ID和产品的匿名对象。接下来，按类型id对这些对象进行分组。现在我们为每种类型的id提供了一组产品。

举个例子，假设您有以下产品和类型：

Product A -- Types 1, 2, 3
Product B -- Types 1
Product C -- Types 1, 3

SelectMany给出以下中间结果：

1, A
2, A
3, A
1, B
1, C
3, C

我们按类型ID对此结果进行分组，因此我们得到以下组：

1, { A, B, C }
2, { A }
3, { A, C }

这就是你想要的结果。

Answer 2

   var types = (from p in productsList
               from t in p.Types
               select t).Distinct(new TypeComparerById());
   var productsGrouped = (from t in types
                         select new 
                         {
                          Type = t,
                          ProductsPerType = productsList.Where(p=>p.Types.Any(pt=>pt.Id == t.Id))
                         }).ToList();

修改
Ronald Wildenberg正确地指出，只有实例相同时，对Distinct（）的调用才会起作用。为了纠正这个问题，我使用以下实现进行更新

public class TypeComparerById : IEqualityComparer<Type> { public bool Equals(Type t1, Type t2) { if (t1.Id == t2.Id) { return true; } else { return false; } } public int GetHashCode(Type t) { return t.Id.GetHashCode(); } }

你应该选择他的答案是正确的（虽然下一个也是正确的）

Answer 3

要查找与每种产品类型相关联的产品数量（产品可以有多种类型），您可以先选择所有不同类型的产品

 var productTypeEqualityComparer = new ProductTypeEqualityComparer();
 var results = productsList.SelectMany(b => b.Types ).Distinct(productTypeEqualityComparer );

然后您可以列出包含每种不同类型的所有产品：

 Dictionary<Type, List<Product>> productsByProductType = new Dictionary<Type, List<Product>>()
 foreach (Type productType in results)
 {
      productsByProductType[productType] = productsList.Where(p => p.Types.Contains(productType, productTypeEqualityComparer )).ToList();
 }

像这样创建你的相等比较器：

 public class ProductTypeEqualityComparer : IEqualityComparer<Type>
{
    public bool Equals(Type x, Type y) {
 // I'm assuming here that the ID is unique to each type, but if it is 
        return x.Id == y.Id; 
    }

    public int GetHashCode(Type obj) {
        return obj.Id.GetHashCode();
    }
}

*编辑添加相等比较器

Answer 4

然后我试图像这样搜索

为此你不需要字典......

代码：

var productsList = new List<Product>();
productsList.Add(new Product { Id = 1, Name = "p1", Types = new List<Type>() { new Type() { Id = 1, Name = "ptype1" }, new Type() { Id = 2, Name = "ptype2" } } });
productsList.Add(new Product { Id = 2, Name = "p2", Types = new List<Type>() { new Type() { Id = 1, Name = "ptype1" } } });
productsList.Add(new Product { Id = 3, Name = "p3", Types = new List<Type>() { new Type() { Id = 2, Name = "ptype2" } } });
productsList.Add(new Product { Id = 4, Name = "p4", Types = new List<Type>() { new Type() { Id = 2, Name = "ptype2" }, new Type() { Id = 3, Name = "type3" } } });

// this is an IEnumerable<Type> (types with the same Id and different name will take only the first)
var productTypesList = (from p in productsList      // for each product
                        from t in p.Types           // for each type in product
                        group t by t.Id into types  // group em by Id into types
                        select types.First());      // but use only the first (else this would be an IEnumerable<IGrouping<Type>>

Console.WriteLine("Types:");

//EDIT: Since Francesca had some complains, and thought having a dictionary from this is difficult, here is a one liner to do that.
// This can be done by surrounding the query above with parenthesis and adding the ToDictionary() call at the end
// I prefer not to use a dictionary unless needed and your code seems not to need it since you need to loop on product types, as stated at the end of the question
// Use this only if you need to store or pass around these values. if you do, you loose potential other properties of your types.
var prodTypeDict = productTypesList.ToDictionary(v => v.Id, v => v.Name);

foreach (var p in productTypesList)
{
    Console.WriteLine(p.Id + " " + p.Name);
}

foreach (var type in productTypesList)
{
    // this is an IEnumerable<Product>
    var products = from p in productsList                   // for each product
                   where p.Types.Any(t => t.Id == type.Id)  // that has this type
                   select p;

    Console.WriteLine("Products of type: " + type.Name);
    foreach (var p in products)
    {
        Console.WriteLine(p.Id + " " + p.Name);
    }

}

输出：

Types:
1 ptype1
2 ptype2
3 type3
Products of type: ptype1
1 p1
2 p2
Products of type: ptype2
1 p1
3 p3
4 p4
Products of type: type3
4 p4

C＃从List <item> </item>中查找所有匹配的项目

4 个答案: