Question

挠我的头。尝试调用函数时出现未定义错误。问题是，当我打印到控制台时，我可以清楚地看到正在传递的数据。

<块引用>

未捕获的类型错误：convos 未定义

功能1

function fetchConversation(userID){

//loop through 
usersms.forEach(function (sms,counter) {

//get userid from  iteration
var userid_loop = sms.details[0].user.id;

//only display convo from specific user
if(userid_loop === userID){

//get all messages from this one user
var conversation = sms.details;

//transfer conversation to next function to display
showConversation(conversation);
//
}
//
});
}

功能2

function showConversation(myconvo){
        
var convos = myconvo;
        
//iterate and append conversion
convos.forEach(function (msg,counter) {
        
console.log(msg.message);//prints all messages in the log
        
});
}
showConversation()//Uncaught TypeError: convos is undefined

Answer 1

我认为您需要在 showConversation() 的括号内输入一些内容。

您正在为 myconvo 分配 convo，但 myconvo 不存在，因为您没有将其作为参数（括号中的值）输入。

Answer 2

您的第一个错误是您没有向函数传递任何参数。

您的第二个错误是 msg.message 不存在 - 它只是 msg 本身。

此外，在这种情况下不需要计数器。

function showConversation(myconvo) {
  var convos = myconvo;
  //iterate and append conversion
  convos.forEach(function(msg) {
    console.log(msg); //prints all messages in the log
  });
}
showConversation(["element1", "element2"])

您在这里也有错误：

function fetchConversation(userID){

//loop through
usersms.forEach(function (sms,counter) {

//get userid from  iteration
var userid_loop = sms.details[0].user.id;

//only display convo from specific user
if(userid_loop === userID){

//get all messages from this one user
var conversation = sms.details; //actually gets the details of the element it is iterating through, not all of them

//transfer conversation to next function to display
showConversation(conversation); //sends the details one by one for each iteration
//
}
//
});
}

修复：

function fetchConversation(userID){
var conversation=[]
//loop through
usersms.forEach(function (sms,counter) {

//get userid from  iteration
var userid_loop = sms.details[0].user.id;

//only display convo from specific user
if(userid_loop === userID){

//get all messages from this one user
conversation.push(sms.details);
}
});
//transfer conversation to next function to display
showConversation(conversation);
}

从另一个函数调用函数时获取未定义的变量

2 个答案: