如何从属性文件转换属性
creditmaster.metadata.AverageFicoScore=700
creditmaster.a.b.c=xyz
以通用的方式转换成这个json格式
{
creditmasterMetaData: [
{
attributeKey: "AverageFicoScore",
attributeValue: 700
}
]
}
答案 0 :(得分:3)
这个脚本是通用的,因为键的部分是什么并不重要,它只按第一个元素(第一个点之前)和最后一个点之后的键名进行分组,它忽略了中:
%dw 2.3
output application/java
import * from dw::core::Strings
fun mapProperties(props) =
entriesOf(props) // since Mule 4.3 / DW 2.3
filter (substringAfter($.key, ".") startsWith "metadata.") // to filter keys with .metadata.
groupBy ((item, index) -> substringBefore(item.key, "."))
mapObject ((value, key, index) ->
(key): value map {
attributeKey: substringAfterLast($.key, "."),
attributeValue: if (isInteger($.value)) $.value as Number else $.value
}
)
---
mapProperties(payload)
输入文件:
creditmaster.metadata.AverageFicoScore= 700
other.a.b= 123
creditmaster.a.b.c=xyz
something.metadata.another.maximum=456
creditmaster.metadata.different.minimum=500
输出(为清晰起见,采用 JSON):
{
"something": [
{
"attributeKey": "maximum",
"attributeValue": "456"
}
],
"creditmaster": [
{
"attributeKey": "minimum",
"attributeValue": "500"
},
{
"attributeKey": "AverageFicoScore",
"attributeValue": "700"
}
]
}
答案 1 :(得分:1)
另一种方法是使用 pluck
函数。它允许您迭代接收条目的对象。
如果你有这个输入
{
"creditmaster": {
"metadata": {
"AverageFicoScore": "700",
"OtherData": "Some value"
}
}
}
有了这个转变
{
creditmasterMetaData:
payload.creditmaster.metadata pluck ((value, key, index) ->
{
attributeKey: key,
attributeValue: value
}
)
}
你得到这个输出
{
"creditmasterMetaData": [
{
"attributeKey": "AverageFicoScore",
"attributeValue": "700"
},
{
"attributeKey": "OtherData",
"attributeValue": "Some value"
}
]
}