Question

给定示例文本，我想提取地址街（星号之间的文本）。使用下面的正则表达式，我能够为大多数句子提取地址街，但主要是 text4 和 text5 失败。

regex = r"(^[0-9]+[\s\-0-9,A-Za-z]+)"
text1 = *9635 E COUNTY ROAD, 1000 N*.
text2 = *8032 LIBERTY RD S*.
text3 = *2915 PENNSYLVANIA AVENUE*  40 Other income (loss) 15 Alternative minimum tax (AMT) ilems
A 2,321
text4 = *2241 Western Ave*. 10 Other income loss 15 — Altemative minimum tax AMT itams
text5 = *450 7TH STREET, APT 2-M*
text6 = *9635 East County Road 1000 North*

My code---
for k,v in val.items():
 if k == "Shareholder Address Street":
   text = " ".join(v)
   pattern1 = r"(^[0-9]+[\s\-0-9,A-Za-z]+)"
   addressRegex = re.compile(pattern1)
   match = addressRegex.search(text)
   if match is not None:
      delta = []
      delta.append("".join(match.group(0)))
      val[k] = delta

任何人都可以建议更改上述正则表达式，因为它适用于大多数文档吗？

Answer 1

使用

^\d+(?:[ \t][\w,-]+)*

见proof

说明

--------------------------------------------------------------------------------
  ^                        the beginning of the string
--------------------------------------------------------------------------------
  \d+                      digits (0-9) (1 or more times (matching
                           the most amount possible))
--------------------------------------------------------------------------------
  (?:                      group, but do not capture (0 or more times
                           (matching the most amount possible)):
--------------------------------------------------------------------------------
    [ \t]                    any character of: ' ', '\t' (tab)
--------------------------------------------------------------------------------
    [\w,-]+                  any character of: word characters (a-z,
                             A-Z, 0-9, _), ',', '-' (1 or more times
                             (matching the most amount possible))
--------------------------------------------------------------------------------
  )*                       end of grouping

从字符串中提取地址街的正则表达式

1 个答案: