Question

如何编写一个程序，用户输入一个数字作为输入（数字最多可以是六位数字），然后程序将其转换为文本？

例如，用户输入 100 并打印输出“一百”。

代码必须是Java。用户最多可随机输入六位数字

我写了一个代码如下，但是是两位数的，多位数的我就留着写了

public static void main(String args[]){
    Scanner sc=new Scanner(System.in);
    System.out.println("enter the number");
    int n=sc.nextInt();
    int n1=n,n2=n;
    int b=n1%10,a=n2/10; //  n1/10 means last digit is removed and n2%10 means last digit by modulus

    String[] single_digits = new String[]{"zero","one","two","three","four","five", "six","seven","eight","nine"};
    String[] two_digits = new String[]{"","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen", "nineteen"};
    String[] tens_multiple = new String[]{"","","twenty","thirty","forty","fifty","sixty", "seventy","eighty","ninety"};
    if(a==1)
    {
        System.out.println(two_digits[b+1]);
    }
    else if(b==0)
        System.out.println(tens_multiple[a]);
    else
        System.out.println(tens_multiple[a]+"-"+single_digits[b]);

Answer 1

破解

您所需要的只是可重用的方法。例如，打印 1 位数字、2 位数字等的方法...然后在打印第一个后在 printOne 中调用 printTwo，如图所示...< /p>

import java.util.Scanner;

public class x {

    // Instance fields are below....
    // Placed below for easy readability of code...

    public static void main (String args[]) {

        // You know what this does...
        System.out.print (" Input number\n > ");
        Scanner sc = new Scanner (System.in);

        // Create int array to collect all digits...
        String number = Integer.toString (sc.nextInt ());
        int[] digits = new int[number.length ()];

        for (int i = 0; i < number.length (); i++)
            digits [i] = Integer.parseInt (number.charAt (i) + "");

        // All you need is a simple method to print a given amount..even up to ten million
        switch (digits.length) {
            case 1:
                printOne (digits);
                break;
            case 2:
                printTwo (digits);
                break;
            case 3:
                printThree (digits);
                break;
            case 4:
                printFour (digits);
                break;
            case 5:
                printFive (digits);
                break;
            case 6:
                printSix (digits);
                break;
        }
    }

    static void printOne (int[] arr) {
        // Just print coresponding value, easy since i converted to int[]
        System.out.print (below_ten [arr [0]]);
    }
    static void printTwo (int[] arr) {
        // check if it is a ~teen/not (you know what i mean)
        if (arr [0] == 1)
            System.out.print (below_twenty [arr [1] + 1]);
        else {
            System.out.print (below_hundered [arr [0]] + " ");
            if (arr [1] != 0) // added this to prevent 30 = thirty zero
                printOne (new int[] {arr [1]}); // this wont be needed for the ~teens
        }
    }
    static void printThree (int[] arr) {
        // now everything is siple, just print first digits and call previous, to call previous...
        // you get where that goes...
        System.out.print (below_thousand [arr [0]] + " ");
        printTwo (new int[] {arr [1], arr [2]});
    }
    // Now you have the algorithm, Challenge=print up to ten million... :-)
    static void printFour (int[] arr) {
        // challenge
    }
    static void printFive (int[] arr) {
        //exercise
    }
    static void printSix (int[] arr) {
        //bounty :-b)
    }

    // Placed below for easy readability of code...
    static String hundred = " hundred";
    static String[] below_ten = new String[] {
        "zero","one","two","three","four","five", "six","seven","eight","nine"
    };
    static String[] below_twenty = new String[] {
        "","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen", "nineteen"
    };
    static String[] below_hundered = new String[] {
        "","","twenty","thirty","forty","fifty","sixty", "seventy","eighty","ninety"
    };
    static String[] below_thousand = new String[] {
        "", below_ten [1] + hundred, below_ten [2] + hundred,  below_ten [3] + hundred,  below_ten [4] + hundred,  below_ten [5] + hundred,  below_ten [6] + hundred,  below_ten [7] + hundred,  below_ten [8] + hundred,  below_ten [9] + hundred,
    };
}

_祝你好运...

编辑如果你在使用其他方法时遇到问题......比魅力更有效......

static void printFour (int[] arr) {
        System.out.print (below_million [arr [0]]);
        printThree (new int[] {arr [1], arr [2], arr [3]});
    }
    static void printFive (int[] arr) {
        printTwo (new int[] {arr [0], arr [1]});
        System.out.print (thousand);
        printThree (new int[] {arr [2], arr [3], arr [4]});
    }
    static void printSix (int[] arr) {
        printThree (new int[] {arr [0], arr [1], arr [2]});
        System.out.print (thousand);
        printThree (new int[] {arr [3], arr [4], arr [5]});
    }
static String thousand = " thousand ";
    static String[] below_million = new String[] {
        "", below_ten [1] + thousand, below_ten [2] + thousand,  below_ten [3] + thousand,  below_ten [4] + thousand,  below_ten [5] + thousand,  below_ten [6] + thousand,  below_ten [7] + thousand,  below_ten [8] + thousand,  below_ten [9] + thousand,
    };

如何将数字转换为文本

1 个答案:

破解

_祝你好运...