如何在类中包含构造函数签名？

Question

所以我有这样一个场景，我执行了一个排除，而我只剩下我预期的类型。当我尝试用我的类型实例化一个类时，我从打字稿编译器中收到此错误 Type 'MyClass' has no construct signatures

class MyClass {
}

type U = Exclude<MyClass | string, string> // U = MyClass

// ...

function example(_myClass: U) {
    const instance = new _myClass();
    // ts error `Type 'MyClass' has no construct signatures`
}

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