Screenshot Game"我正在制作一个游戏,我想创建一个当玩家跳到一个盒子上并弹跳时的弹跳脚本 起来,这是我目前所拥有的”
public Rigidbody rb;
public float bounceForce = 3f;
// Start is called before the first frame update
void Start()
{
rb = GetComponent<Rigidbody>();
}
void OnTriggerEnter(Collider coll) {
if(coll.gameObject.tag == "Player"){
Debug.Log("Jumpforce");
GetComponent<Rigidbody>().AddForce (0,bounceForce,0);
}
}
答案 0 :(得分:0)
我知道了
openDialog(): void {
const dialogRef = this.dialog.open(DialogOverviewExampleDialog, {
width: '250px',
data: {
name: this.name,
animal: this.animal,
requestForm: this.requestForm
}
});