我有一个名为 Calculation 的类,我添加了两个函数 addOperationToName() 和 sayOperation() 作为装饰器设计模式的示例。但是,当我使用 Jest 对其进行测试时,出现“fn 不是函数”的错误。有人可以帮我吗?
计算.js
class Calculation {
constructor(a, b, op) {
this.a = a;
this.b = b;
this.op = op;
}
static Create(a, b, op){
return new Calculation(a, b, op);
}
GetResults() {
return this.op(this.a,this.b)
}
addOperationToName(fn){
return function(name){
const operation = name + ' is a operation';
fn(operation);
}
}
sayOperation(name){
console.log(name);
}
}
module.exports = Calculation;
Calculation.test.js
const Calculation = require('../src/models/Calculation');
test('Test say name for Product operation', () => {
let op = Product;
let calculation = new Calculation(1,2,op);
let sayTest = calculation.addOperationToName(calculation.sayOperation());
expect(sayTest('Multiply')).toBe('Multiply is an operation');
});
答案 0 :(得分:1)
您应该将函数传递给 addOperationToName
,现在您正在返回函数的 结果 - 只需将 calculation.addOperationToName(calculation.sayOperation());
更改为 calculation.addOperationToName(calculation.sayOperation);
>
class Calculation {
constructor(a, b, op) {
this.a = a;
this.b = b;
this.op = op;
}
static Create(a, b, op){
return new Calculation(a, b, op);
}
GetResults() {
return this.op(this.a,this.b)
}
addOperationToName(fn){
return function(name){
const operation = name + ' is a operation';
return fn(operation);
}
}
sayOperation(name){
console.log(name);
return name;
}
}
let calculation = new Calculation(1,2,null);
let sayTest = calculation.addOperationToName(calculation.sayOperation);
console.log(sayTest('Multiply') === 'Multiply is a operation')