if 语句中无法识别输入

Question

choice = input('Are you ready to start the test (Y/N): ')
print (choice)
while choice not in ['Y','N',]:
    choice = input('Invalid choice. Are you ready to start the test (Y/N): ')
    print(choice)
    if choice  == 'N':
        sys.exit
    if choice == 'Y':
        print('Test starts in 3...')
        time.sleep(1)
        print('2...')
        time.sleep(1)
        print('1...')
        time.sleep(1)
        countdown(t)6
        print('BEGIN')

输出：

Welcome to type test
You will be given sixty seconds to type as many correct words as possible!
Are you ready to start the test (Y/N): Y
Y

Answer 1

我在本地使用了您的代码，缩进如下，并且运行良好：

import time
import sys

choice = input('Are you ready to start the test (Y/N): ')
print (choice)
while choice not in ['Y','N',]:
    choice = input('Invalid choice. Are you ready to start the test (Y/N): ')
print(choice)
if choice  == 'N':
    sys.exit
if choice == 'Y':
    print('Test starts in 3...')
    time.sleep(1)
    print('2...')
    time.sleep(1)
    print('1...')
    time.sleep(1)
    #countdown(t)
    print('BEGIN')