Question

我想知道如何检查字符串格式是否匹配

“111 + 222”

像这样的字符串，格式应该是

(double type number)+(white space)+(operand(+,-,*,/,^))+(white space)+(double type number)

我知道我应该使用匹配来做到这一点，但我如何用空格处理它？</p>

Answer 1

是的，您可以使用模式匹配器或字符串匹配器。

public static void main(String[] args) throws Exception {
    String pattern = "-?[\\d\\.]{3,4}\\s[+\\-*/^]\\s-?[\\d\\.]{3,4}";
    System.out.println(matchWithPatternMatcherCompile(pattern, "111 + 222")); // True
    System.out.println(matchWithPatternMatcher(pattern, "111 + 222")); // True
    System.out.println(matchWithStringRegex(pattern, "111 + 222")); // True
    System.out.println(matchWithPatternMatcherCompile(pattern, "111 + -2.22")); // True
    System.out.println(matchWithPatternMatcher(pattern, "11.1 + 222")); // True
    System.out.println(matchWithStringRegex(pattern, "-111 + 222")); // True
}

private static boolean matchWithStringRegex(String regex, String input) {
    return input.matches(regex);
}

private static boolean matchWithPatternMatcherCompile(String regex, String input) {
    Pattern pattern = Pattern.compile(regex);
    Matcher matcher = pattern.matcher(input);
    return matcher.matches();
}

private static boolean matchWithPatternMatcher(String regex, String input) {
    return Pattern.matches(regex, input);
}

如何检查字符串是否与特定格式匹配？

1 个答案: