Question

这是我和我的BlockingQueue ......我根据this article和this question重写了它。它会发送一些项目，然后因访问冲突而崩溃。这是代码：

template <typename T>
bool DRA::CommonCpp::CTBlockingQueue<T>::Push( T pNewValue ){
    volatile long oldSize;
    ::InterlockedExchange( &oldSize, m_Size );
    CTNode* pNewNode = new CTNode();
    pNewNode->m_pValue = pNewValue;
    {//RAII block
        CGuard g( m_TailCriticalSection );
        m_pTailNode->m_pNext = pNewNode;
        m_pTailNode = pNewNode;
        ::InterlockedIncrement( &m_Size );
    }
    if( oldSize == 0 )
        m_eAtLeastOneElement.set();
    return true;
}

template <typename T>
bool DRA::CommonCpp::CTBlockingQueue<T>::Pop( T& pValue ){
    CTNode* pCurrentNode;
    {//RAII block
        CGuard g( m_HeadCriticalSection );
        pCurrentNode = m_pHeadNode;
        CTNode* pNewHeadNode = m_pHeadNode->m_pNext;
        if( pNewHeadNode == NULL ){
            CEvent* pSignaledEvent;
            CEvent::waitForPair( m_eAtLeastOneElement, m_eFinished, pSignaledEvent );
            if( pSignaledEvent == &m_eFinished )
                return false;
            pNewHeadNode = m_pHeadNode->m_pNext;
        }
        pValue = pNewHeadNode->m_pValue;
        m_pHeadNode = pNewHeadNode;
        ::InterlockedDecrement( &m_Size );
    }
    delete pCurrentNode;
    return true;
}

它总是在调用Pop（）之后崩溃，在if之后的行中，那个说：

pValue = pNewHeadNode->m_pValue

它炸毁cos'pNewHeadNode为NULL。但是这怎么可能发生呢？

编辑：忘记初始化代码：

template <typename T>
DRA::CommonCpp::CTBlockingQueue<T>::CTBlockingQueue():
        m_HeadCriticalSection("CTBlockingQueue<T>::m_Head"),
        m_TailCriticalSection("CTBlockingQueue<T>::m_Tail"){
    CTNode* pDummyNode = new CTNode();
    m_pHeadNode = pDummyNode;
    m_pTailNode = pDummyNode;
    m_Size = 0; //Dummy node doesn't count
}

Answer 1

我的假设必须是事件被设置在关键部分之外，这意味着push可能会通知事件两次。您是否尝试过在关键部分内设置事件？

Answer 2

最后，我回到原来的，效率较低的实现，即我发布here的实现，添加了一个Finish（）方法，以便生产者可以发信号通知消费者优雅地结束，一个Restart（）方法，可以在不破坏和重新创建队列的情况下再次开始生成：

//Template definitions
template<class Element>
DRA::CommonCpp::CTBlockingQueue<Element>::CTBlockingQueue( unsigned int maxSize ):
    m_csFinished( "CTBlockingQueue::m_csFinished" ),
    m_csQueue( "CTBlockingQueue::m_csQueue" ),
    m_semElementCount( 0, maxSize ),
    m_bFinished(false){
}

template<class Element>
DRA::CommonCpp::CTBlockingQueue<Element>::~CTBlockingQueue(){
    Finish();
}

template<class Element>
void DRA::CommonCpp::CTBlockingQueue<Element>::Push( Element newElement ){
    {//RAII block
        CGuard g( m_csQueue );
        m_Queue.push( newElement );
    }
    m_semElementCount.Signal();
}

template<class Element>
bool DRA::CommonCpp::CTBlockingQueue<Element>::Pop( Element& element ){
    m_semElementCount.Wait();
    {//RAII block
        CGuard g( m_csFinished );
        if( m_bFinished ){
            CGuard g( m_csQueue );
            if ( m_Queue.size() == 0 )
                return false;
        }
    }
    {//RAII block
        CGuard g( m_csQueue );
        element = m_Queue.front();
        m_Queue.pop();
    }
    return true;
}

template<class Element>
void DRA::CommonCpp::CTBlockingQueue<Element>::Finish(){
    {//RAII block
        CGuard g( m_csFinished );
        m_bFinished = true;
    }
    {//RAII block
        CGuard g( m_csQueue );
        m_semElementCount.Signal();
    }
}

template<class Element>
void DRA::CommonCpp::CTBlockingQueue<Element>::Restart(){
    {//RAII block
        CGuard g( m_csFinished );
        m_bFinished = false;
    }
}

这不是最快的方式，但对我来说工作得足够快。

阻止队列实施：竞争条件在哪里？

2 个答案: