所以我更新了 firebase_messaging 并且我不得不更改我的代码，因为 onChange 已被弃用，现在当我收到通知并点击通知时，它不会打开另一个屏幕。
这是我实现通知的方式：
FirebaseMessagin.configure()但是当我点击通知时没有调用 Future<void> _firebaseMessagingBackgroundHandler(RemoteMessage message) async {
await Firebase.initializeApp();
print('Handling a background message ${message.messageId}');
}
const AndroidNotificationChannel channel = AndroidNotificationChannel(
'high_importance_channel', // id
'High Importance Notifications', // title
'This channel is used for important notifications.', // description
importance: Importance.high,
);
final FlutterLocalNotificationsPlugin flutterLocalNotificationsPlugin =
FlutterLocalNotificationsPlugin();
Future<void> main() async {
WidgetsFlutterBinding.ensureInitialized();
FirebaseMessaging.onBackgroundMessage(_firebaseMessagingBackgroundHandler);
runApp(MyApp());
}
class MyApp extends StatelessWidget {
const MyApp({Key key}) : super(key: key);
@override
Widget build(BuildContext context) {
return MaterialApp(
title: 'e-Rădăuți',
debugShowCheckedModeBanner: false,
initialRoute: '/',
routes: {
'/': (_) => MenuScreen(),
'/events': (BuildContext context) => EventsScreen(),
},
);
}
}
class MenuScreen extends StatefulWidget {
@override
_MyAppState createState() => new _MyAppState();
}
Widget build(BuildContext context) {
return Scaffold();
}
@override
void initState() {
super.initState();
FirebaseMessaging.onMessage.listen((RemoteMessage message) {
RemoteNotification notification = message.notification;
AndroidNotification android = message.notification?.android;
if (notification != null && android != null) {
flutterLocalNotificationsPlugin.show(
notification.hashCode,
notification.title,
notification.body,
NotificationDetails(
android: AndroidNotificationDetails(
channel.id,
channel.name,
channel.description,
icon: 'launch_background',
),
));
}
});
FirebaseMessaging.onMessageOpenedApp.listen((RemoteMessage message) {
debugPrint('A new onMessageOpenedApp event was published!');
Navigator.pushNamed(context, '/events');
});
}
}
，因为我在我的控制台 (VSCode) 中没有收到 .onMessageOpenedApp 消息并且我收到以下错误：
debugPrint我使用 D/FLTFireMsgReceiver( 4799): broadcast received for message
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->add(I)Z (greylist,test-api, reflection, allowed)
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->add(ILjava/lang/String;)Z (greylist,test-api, reflection, allowed)
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->get(I)I (greylist, reflection, allowed)
W/civic.e_radaut( 4799): Accessing hidden method Landroid/os/WorkSource;->getName(I)Ljava/lang/String; (greylist, reflection, allowed)
W/FirebaseMessaging( 4799): Notification Channel set in AndroidManifest.xml has not been created by the app. Default value will be used.
I/flutter ( 4799): Handling a background message 0:1617783965733220%2ebdcc762ebdcc76
从 Firebase 发送了我的通知，并在我的清单中添加了
click_action: FLUTTER_NOTIFICATION_CLICK我的 <intent-filter>
<action android:name="FLUTTER_NOTIFICATION_CLICK" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
版本是 firebase_messaging
所以我不知道我错过了什么或者为什么它不起作用。如果您需要更多详细信息，请随时询问。
答案 0 :(得分：4)
我使用 .getInitialMessaging() 函数解决了这个问题（这是应用终止时的回调。当应用处于后台但未终止时，我的通知有效。
为了解决这个问题，我只是将它添加到我的代码中：
FirebaseMessaging.instance
.getInitialMessage()
.then((RemoteMessage message) {
if (message != null) {
Navigator.pushNamed(context, message.data['view']);
}
});
我制作了一个工作演示here
答案 1 :(得分：0)
如果您想在应用启动前点击通知时转到任何页面或午餐链接，则必须使用
<块引用>getInitialMessage()
示例：
FirebaseMessaging.instance
.getInitialMessage()
.then((RemoteMessage message) {
if (message != null) {
//to do your operation
launch('https://google.com');
}
});
答案 2 :(得分：-1)
当应用程序在后台时它应该可以工作，但是当它被终止时你应该使用 getInitialMessage。
onMessageOpenedApp：如果应用程序从后台状态打开（未终止），则将发送 Stream 事件。
如果您的应用在应用终止时通过通知打开，请参阅getInitialMessage。