Question

现在对于带有字符串“shirt”的每个项目，我想将衬衫替换为“衬衫不可用

const inventory = [
        { line_item_id: "55412", item: "Shirt small", description: "" },
        { line_item_id: "55342", item: "shirt big full", description: "" },
        { line_item_id: "1124",  item: "Pant Small",description: "",},
    ];

我希望它看起来像这样

const inventory = [
    { line_item_id: "55412", item: "Shirts are not available small", description: "" },
    { line_item_id: "55342", item: "Shirts are not available big full", description: "" },
    { line_item_id: "1124",  item: "Pant Small",description: "",},
];

我使用了 map 函数，但它不包括未被修改的行

我的代码

  const test = convertedToJson.map((convertedToJson) => {
        if (!!convertedToJson.item.match(/Shirt/i)) {
            return convertedToJson.item + "Shirts are not available  ";
        }
    });
    console.log(test);

“我的输出”

const inventory = [
       'Shirts are not available small'
        'Shirts are not available big full'
    ];

Answer 1

const convertedInventory = inventory.map((it) => {
  const reg = new RegExp(/Shirt/i);
  if (it.item.match(reg)) {
    return {
      ...it,
      item: it.item.replace(reg, 'Shirts are not available')
    }
  }
  return it;
})

Answer 2

您可以使用地图和替换

const inventory = [{
    line_item_id: "55412",
    item: "Shirt small",
    description: ""
  },
  {
    line_item_id: "55342",
    item: "shirt big full",
    description: ""
  },
  {
    line_item_id: "1124",
    item: "Pant Small",
    description: "",
  },
];

const newVal = inventory.map((elem) => {
  // checking if string contains shirt/Shirt
  if (elem.item.toLowerCase().indexOf('shirt') !== -1) {
    return {
      ...elem,
      // case-insensitive replacement
      item: elem.item.replace(/shirt/gi, "Shirts are not available")

    }
  } else {
    return { ...elem
    }
  }
});

console.log(newVal)

Answer 3

const test = convertedToJson.map((convertedToJson) => {
        if (convertedToJson.item.toLowerCase().indexOf('shirt') !== -1) {
            convertedToJson.item = convertedToJson.item.replace(/shirt/gi, "Shirts are not available");
        }
        return convertedToJson
    });
    console.log(test);

您的代码的问题是只有在条件满足时才返回值。我只是返回外部的值，如果“如果条件”得到满足，则该值将被操纵

Answer 4

这边...

const inventory = 
  [ { line_item_id: "55412", item: "Shirt small",    description: "" } 
  , { line_item_id: "55342", item: "shirt big full", description: "" } 
  , { line_item_id: "1124",  item: "Pant Small",     description: "" } 
  ] 

inventory.forEach((obj,i,arr)=>
  arr[i].item = obj.item.replace(/shirt/i, 'Shirts are not available'))

console.log( inventory )

.as-console-wrapper {max-height: 100%!important;top:0;}

Answer 5

您可以使用 Array.prototype.map 轻松实现这一点。

const inventory = [{
    line_item_id: "55412",
    item: "Shirt small",
    description: ""
  },
  {
    line_item_id: "55342",
    item: "shirt big full",
    description: ""
  },
  {
    line_item_id: "1124",
    item: "Pant Small",
    description: ""
  },
];

const result = inventory.map((el) => {
  if (el.item.toLowerCase().includes("shirt")) {
    return { ...el,
      item: "Shirts are not available small"
    };
  }
  return el;
});


console.log( result );

我只想将文本附加到对象

5 个答案: