如何关闭打开用于写入然后读取的临时文件

Question

我有一个场景，我必须打开一个临时文件，将 csv 数据写入其中，然后将其作为 POST 调用的附件读取，然后将其删除。

我正在尝试的是：

    import tempfile, os, csv

    tf = tempfile.NamedTemporaryFile(delete=False)
        try:
            with open(tf.name, 'w', newline='') as csvfile:
                csvwriter = csv.writer(csvfile, delimiter=',')
                csvwriter.writerows(resources)
        except Exception as e:
            LOG.error(e)
        try:
            with open(tf.name, 'r') as f:
                files = {'attachment': ('some.csv',
                                        f, 'text/csv')}
                try:
                    retval = group.file_upload(payload=payload, files=files)
                except Exception as e:
                    LOG.error(e)
        except Exception as e:
            LOG.error(e)
        print(tf.name)
        tf.close()
#       os.remove(tf.name)

但是 tf.close 没有删除文件... os.remove 抛出错误 PermissionError: [WinError 32] The process cannot access the file because it is being used by another process 有什么办法可以删除这个文件吗？