Question

我有一个场景，我有以下数据：

表格：位置

ID      TYPE
------------------
1000    STORE
11001   STORE
20000   STORE
1181    WAREHOUSE
12002   STORE

我想以一种方式排序，即所有以“0000”结尾的 ID 都应该先排序，然后是 TYPE 'Warehouse'，然后是其余的 Stores。

所需的输出应该是这样的

ID      TYPE
------------------
10000   STORE
20000   STORE
1181    WAREHOUSE
11001   STORE
12002   STORE

如何进行这种自定义排序？

Answer 1

您可以在排序中使用 case 表达式：

order by (case when id like '%0000' then 1
               when type = 'WAREHOUSE' then 2
               else 3
          end), id

这也使用 id 在三个组内排序。

注意：如果 id 是数字而不是字符串，我建议：

order by (case when mod(id, 10000) = 0 then 1
               when type = 'WAREHOUSE' then 2
               else 3
          end), id

[由 LF 编辑]

这是你的 ORDER BY 返回的，这不是 OP 想要的：

SQL> with locations (id, type) as
  2    (select 1000 , 'STORE'     from dual union all
  3     select 11001, 'STORE'     from dual union all
  4     select 20000, 'STORE'     from dual union all
  5     select 1181 , 'WAREHOUSE' from dual union all
  6     select 12002, 'STORE'     from dual
  7    )
  8  select id, type
  9  from locations
 10  order by (case when id like '%0000' then 1
 11                 when type = 'WAREHOUSE' then 2
 12                 else 3
 13            end), id;

        ID TYPE
---------- ---------
     20000 STORE
      1181 WAREHOUSE
      1000 STORE
     11001 STORE
     12002 STORE

SQL>

Gordon 的评论：如果 1000 行是 10000，以上应该可以工作。

Answer 2

我是这样理解问题的；采样数据直到第 7 行；查询从第 8 行开始。

SQL> with locations (id, type) as
  2    (select 1000 , 'STORE'     from dual union all
  3     select 11001, 'STORE'     from dual union all
  4     select 20000, 'STORE'     from dual union all
  5     select 1181 , 'WAREHOUSE' from dual union all
  6     select 12002, 'STORE'     from dual
  7    )
  8  select id, type
  9  from locations
 10  order by case when substr(to_char(id), -3) = '000' then 1 end,
 11           case when type = 'WAREHOUSE' then 2 end,
 12           type;

        ID TYPE
---------- ---------
      1000 STORE
     20000 STORE
      1181 WAREHOUSE
     12002 STORE
     11001 STORE

SQL>

Oracle SQL - 自定义排序

2 个答案: