public class Foo {
public static void main(String[] args) {
foo();
}
public static void foo() {
try {
System.out.println("try");
foo();
} catch (Throwable e) {
System.out.println("catch");
foo();
} finally {
System.out.println("finally");
foo();
}
}
}
谁可以解释这段代码的输出?
1.在eclipse(无尽)客户端模式下输出:
try try .... ... ... tryfinallyfinally tryfinallyfinally try try try tryfinallyfinally tryfinallyfinally try tryfinallyfinally tryfinallyfinally try .... ....
2.在linux(崩溃)服务器模式下的输出:
try try ... ... try try try try try try MISSING EXCEPTION HANDLER for pc 0x00002aaaab1c53f0 and handler bci -1 Exception: Compiled exception table : ExceptionHandlerTable (size = 3304 bytes) catch_pco = 700 (1 entries) bci -1 at scope depth 0 -> pco 11039 catch_pco = 1736 (1 entries) bci -1 at scope depth 0 -> pco 11473 catch_pco = 1756 (1 entries) bci -1 at scope depth 0 -> pco 11433 catch_pco = 1776 (1 entries)
答案 0 :(得分:8)
我想我从“Java Puzzlers”一书中记得这一点。 try块执行无限递归,很快导致抛出StackOverflowError。 try和catch阻止恢复递归,但剩余堆栈相应较小。但是,当每个递归调用返回时,剩余的堆栈会再次变大......
最终结果是一个调用图,它根据堆栈的大小形成一个深度为树的树;使用主流JVM的默认堆栈大小,树变得如此之大,以至于你必须等待很多次,很多数十亿年才能完全遍历它并终止程序。
编辑:这就是您在客户端模式下看到的内容:遍历调用图。您在Linux服务器模式下看到的是JVM错误或硬件缺陷(错误的RAM可能会产生这种影响)。