Question

为什么我会收到此错误？

我的Models.py：

    # -*- coding: utf-8 -*-
from django.db import models
from sitem.ligler.models import *
from sitem.takimlar.models import *
from sitem.futbolcular.models import *
from sitem.stadyumlar.models import *
from sitem.ligmaclari.models import *

DAKIKA_SECIMLERI = [(str(dk), str(dk)) for dk in range(1, 121)]
KART_SECIMLER = (
    ('SK','Sari Kart'),
    ('SKK','Sarıdan Kırmızı Kart'),
    ('DKK','Direk Kırmızı Kart')
)
# Create your models here.
class EvSahibiKartlar(models.Model):
    mac = models.ForeignKey(Ligmaclari)
    ev_sahibi_oyuncu = models.ForeignKey(Futbolcular, limit_choices_to = Ligmaclari.ev_sahibi_takim_kadro, related_name='Ev Sahibi Oyuncu')
    kart_tipi = models.CharField(max_length=50, choices=KART_SECIMLER)
    dakika = models.PositiveSmallIntegerField(max_length=4, choices=DAKIKA_SECIMLERI)

    def __unicode__(self):
        return self.mac

class KonukKartlar(models.Model):
    mac = models.ForeignKey(Ligmaclari)
    konuk_takim_oyuncu = models.ForeignKey(Futbolcular, limit_choices_to = Ligmaclari.konuk_takim_kadro, related_name='Konuk Takım Oyuncu')
    kart_tipi = models.CharField(max_length=50, choices=KART_SECIMLER)
    dakika = models.PositiveSmallIntegerField(max_length=4, choices=DAKIKA_SECIMLERI)

    def __unicode__(self):
        return self.mac

我的admin.py：

from sitem.kartlar.models import *
from django.contrib import admin
from django import forms
from django.forms import ModelForm

class EvSahibiKartlarAdmin(admin.ModelAdmin):
    ordering = ['mac']

class KonukKartlarAdmin(admin.ModelAdmin):
    ordering = ['mac']
admin.site.register(EvSahibiKartlar,EvSahibiKartlarAdmin)
admin.site.register(KonukKartlar,KonukKartlarAdmin)

其实我想过滤ForeignKeys ......

Answer 1

limit_choices_to未被传递a valid value。

Answer 2

问题有点老了，但是如果您要进行复杂的查询（例如，嵌套外键过滤），则可以使用类models.Q并直接分配给limit_choices_to

来自docs

limit_choices_to 是或返回Q对象，这对于复杂的查询

示例：

from django.db import models


class Model1(models.Model):
    name = models.CharField(max_length=255)
    is_active = models.BooleanField(default=True)

    class Meta:
        ordering = ("id",)

class Model2(models.Model):
    name = models.CharField(max_length=255)
    model_1 = models.ForeignKey(Model1, on_delete=models.CASCADE)

    class Meta:
        ordering = ("id",)

class Model3(models.Model):
    name = models.CharField(max_length=255)
    model_2 = models.ForeignKey(Model2, on_delete=models.DO_NOTHING, limit_choices_to=models.Q(model_1__is_active=True))

    class Meta:
        ordering = ("id",)

Answer 3

受https://stackoverflow.com/a/26203568/2144569

启发的解决方案

您（以及我）在将查询集传递给limit_choices_to时遇到此错误，而是直接传递pk（即：{pk__in:pks}）并且它将起作用：

我在尝试删除limit_choices_to中的重复时遇到此错误

limit_choices_to = Q(attr1=True) | Q(attr2=True) | Q(attr3=True)

我试着这样做：

def my_func():
    return MyModel.objects.filter(Q(attr1=True) | Q(attr2=True) | Q(attr3=True)).distinct().all()

class HeadModel(models.Model):
    mtm = models.ManyToManyField(
        MyModel,
        limit_choices_to=my_func,
    )

但我得到了上面的错误，因为它是一个查询集。最后我做了

def my_func():
    return {'pk__in':MyModel.objects.filter(Q(attr1=True) | Q(attr2=True) | Q(attr3=True)).distinct().values_list('id', flat=True)}

class HeadModel(models.Model):
    mtm = models.ManyToManyField(
        MyModel,
        limit_choices_to=my_func,
    )

P.S：是的，这是一个非常古老的帖子，但需要是/仍然在这里

**之后的_filter_or_exclude（）参数必须是映射，而不是ReverseManyRelatedObjectsDescriptor

3 个答案: