Question

我想使用 Python 用正则表达式检测公司名称。

这是我的想法：

公司名称应包含 1 到 3 个单词
公司名称中的第一个单词应大写
公司名称中的一个词可以是 .com 或 .co (Amazon.com Inc)
公司名称的最后一个字（第四个字）应为 Inc. , Ltd、GmbH、AG、GmbH、Group、Holding 等。
在名称的最后一个单词和 Inc. , Ltd, GmbH, AG 之间有时可以是 ',' 或 ', '

我尝试过类似的方法，但它不起作用：

address_1 = 'I work in Amazon.com Inc.'
address_2 = 'Company named Swiss Medic Holding invested in vaccine'
address_3 = 'what do you think about Abercrombie & Fitch Co. ?'
address_4 = 'do you work in Delta Group?'
address_5 = 'I have worked in CocaCola Gmbh'

regex_company = '([A-Z][\w]+[ -]+){1,3}(Ltd|ltd|LTD|llc|LLC|Inc|inc|INC|plc|Corp|Group)'
found = re.search(regex_company, address)

我想打印检测到的公司的结果我使用相同的正则表达式逻辑来查找街道地址并且效果很好，但对于公司名称则不然。这是我使用过的正则表达式：

regex_street = "(\d{0,6})(?:\w)\s([A-Z][\w]+[ -]+){1,3}(Street|St|Road|Rd)

正则表达式逻辑：数字+1-3个单词+street/st/road/rd

Answer 1

使用

\b[A-Z]\w+(?:\.com?)?(?:[ -]+(?:&[ -]+)?[A-Z]\w+(?:\.com?)?){0,2}[,\s]+(?i:ltd|llc|inc|plc|co(?:rp)?|group|holding|gmbh)\b

见regex proof。

说明

--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  [A-Z]                    any character of: 'A' to 'Z'
--------------------------------------------------------------------------------
  \w+                      word characters (a-z, A-Z, 0-9, _) (1 or
                           more times (matching the most amount
                           possible))
--------------------------------------------------------------------------------
  (?:                      group, but do not capture (optional
                           (matching the most amount possible)):
--------------------------------------------------------------------------------
    \.                       '.'
--------------------------------------------------------------------------------
    co                       'co'
--------------------------------------------------------------------------------
    m?                       'm' (optional (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )?                       end of grouping
--------------------------------------------------------------------------------
  (?:                      group, but do not capture (between 0 and 2
                           times (matching the most amount
                           possible)):
--------------------------------------------------------------------------------
    [ -]+                    any character of: ' ', '-' (1 or more
                             times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
    (?:                      group, but do not capture (optional
                             (matching the most amount possible)):
--------------------------------------------------------------------------------
      &                        '&'
--------------------------------------------------------------------------------
      [ -]+                    any character of: ' ', '-' (1 or more
                               times (matching the most amount
                               possible))
--------------------------------------------------------------------------------
    )?                       end of grouping
--------------------------------------------------------------------------------
    [A-Z]                    any character of: 'A' to 'Z'
--------------------------------------------------------------------------------
    \w+                      word characters (a-z, A-Z, 0-9, _) (1 or
                             more times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
    (?:                      group, but do not capture (optional
                             (matching the most amount possible)):
--------------------------------------------------------------------------------
      \.                       '.'
--------------------------------------------------------------------------------
      co                       'co'
--------------------------------------------------------------------------------
      m?                       'm' (optional (matching the most
                               amount possible))
--------------------------------------------------------------------------------
    )?                       end of grouping
--------------------------------------------------------------------------------
  ){0,2}                   end of grouping
--------------------------------------------------------------------------------
  [,\s]+                   any character of: ',', whitespace (\n, \r,
                           \t, \f, and " ") (1 or more times
                           (matching the most amount possible))
--------------------------------------------------------------------------------
  (?i:                     group, but do not capture (case-
                           insensitive) (with ^ and $ matching
                           normally) (with . not matching \n)
                           (matching whitespace and # normally):
--------------------------------------------------------------------------------
    ltd                      'ltd'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    llc                      'llc'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    inc                      'inc'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    plc                      'plc'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    co                       'co'
--------------------------------------------------------------------------------
    (?:                      group, but do not capture (optional
                             (matching the most amount possible)):
--------------------------------------------------------------------------------
      rp                       'rp'
--------------------------------------------------------------------------------
    )?                       end of grouping
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    group                    'group'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    holding                  'holding'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    gmbh                     'gmbh'
--------------------------------------------------------------------------------
  )                        end of grouping
--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char

Python code：

import re

regex = r"\b[A-Z]\w+(?:\.com?)?(?:[ -]+(?:&[ -]+)?[A-Z]\w+(?:\.com?)?){0,2}[,\s]+(?i:ltd|llc|inc|plc|co(?:rp)?|group|holding|gmbh)\b"

test_str = ("I work in Amazon.com Inc.\n"
    "Company named Swiss Medic Holding invested in vaccine\n"
    "what do you think about Abercrombie & Fitch Co. ?\n"
    "do you work in Delta Group?\n"
    "I have worked in CocaCola Gmbh")

print(re.findall(regex, test_str))

结果：['Amazon.com Inc', 'Swiss Medic Holding', 'Abercrombie & Fitch Co', 'Delta Group', 'CocaCola Gmbh']

Answer 2

使用 https://regex101.com 测试正则表达式，很棒。对于您的具体示例，这里是可以满足您要求的正则表达式。在此示例中，我认为不需要测试可选的 .com。

regex_company = '[A-Z]([^ ]*[ &]*){0,2}(Inc\.|Ltd|GmbH|AG|Gmbh|Group|Holding|Co\.)'

for address in [address_1, address_2, address_3, address_4, address_5]:
    found = re.search(regex_company, address)
    if found:
        print(found)

# prints:
# <regex.Match object; span=(10, 25), match='Amazon.com Inc.'>
# <regex.Match object; span=(14, 33), match='Swiss Medic Holding'>
# <regex.Match object; span=(24, 47), match='Abercrombie & Fitch Co.'>
# <regex.Match object; span=(15, 26), match='Delta Group'>
# <regex.Match object; span=(17, 30), match='CocaCola Gmbh'>

Python 中检测公司名称的正则表达式

2 个答案: