Question

from collections import Counter

with open("text.txt", encoding='utf-8') as file:
    data = file.read()
    words = data.split()

count_dict = dict(Counter(words))

for key, value in sorted(count_dict.items(), key=lambda x: x[1], reverse=True):
    print(f'{key}: {value} time(s)')

对于文件：

abc  
aab  
abc  
abb  
abb

返回：

abc: 2 time(s)
abb: 2 time(s)
aab: 1 time(s)

虽然它应该返回：

abb: 2 time(s)  
abc: 2 time(s)  
aab: 1 time(s)

在按次数（值？）排序后，如何按字母顺序放置单词（键）？

Answer 1

需要稍作改动：

不是为 sorted 函数指定 reverse-True，而是使用计数的负值。现在我们正在使用计数的负数进行升序排序，我们可以使用包含键作为“辅助列”的组合键进行排序：

for key, value in sorted(count_dict.items(), key=lambda x: (-x[1], x[0])):
    print(f'{key}: {value} time(s)')

综合起来：

from collections import Counter

with open("text.txt", encoding='utf-8') as file:
    data = file.read()
    words = data.split()

count_dict = dict(Counter(words))

for key, value in sorted(count_dict.items(), key=lambda x: (-x[1], x[0])):
    print(f'{key}: {value} time(s)')

印刷品

abb: 2 time(s)
abc: 2 time(s)
aab: 1 time(s)

Answer 2

您可以将负号与 values 一起使用，然后像这样优先使用 keys -

>>> from collections import Counter
>>> l = ["abc","aab","abc","abb","abb"]
>>> l
['abc', 'aab', 'abc', 'abb', 'abb']
>>> count_dict = Counter(l)

#### Negative Value is assigned to count_dict values
>>> sorted(count_dict.items(), key=lambda x: (-x[1],x[0]))
[('abb', 2), ('abc', 2), ('aab', 1)]

>>> for key, value in sorted(count_dict.items(), key=lambda x: (-x[1],x[0])):
...     print(f'{key}: {value} time(s)')
... 
abb: 2 time(s)
abc: 2 time(s)
aab: 1 time(s)
>>>

Answer 3

您希望值（数字）按降序排序，键（单词）按升序排序。你可以试试这个：

sorted(count_dict.items(), key=lambda x: (-x[1], x[0]))

排序键中的负值可以完成这项工作。

如何在按值排序后按字母顺序对字典的键进行排序？

3 个答案: