我在JScrollPane中有一个JPanel,只要我尝试滚动它就会这样做。请帮忙! 如何解决此问题?
修改
JScrollPane pane;
....
pane = new JScrollPane(GC.createGraph());
pane.setPreferredSize(new Dimension(480,480*2/3));
答案 0 :(得分:3)
作为别人看的答案。如果你不调用super.paintComponent,你将获得这些工件。如,
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import javax.swing.*;
public class ScrollPaneArtifacts extends JPanel {
private static final int SPA_WIDTH = 600;
private static final int SPA_HEIGHT = SPA_WIDTH;
@Override
protected void paintComponent(Graphics g) {
//super.paintComponent(g);
g.setColor(Color.red);
g.drawLine(0, 0, getWidth(), getHeight());
g.drawLine(getWidth(), 0, 0, getHeight());
}
@Override
public Dimension getPreferredSize() {
return new Dimension(SPA_WIDTH, SPA_HEIGHT);
}
private static void createAndShowUI() {
JScrollPane scrollpane = new JScrollPane(new ScrollPaneArtifacts());
scrollpane.getViewport().setPreferredSize(new Dimension(400, 400));
JFrame frame = new JFrame("ScrollPaneArtifacts");
frame.getContentPane().add(scrollpane);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
public static void main(String[] args) {
java.awt.EventQueue.invokeLater(new Runnable() {
public void run() {
createAndShowUI();
}
});
}
}
答案 1 :(得分:0)
你不需要调用super.paintComponent就可以简单地清除该区域,以确保在前面的渲染(调用super.paintComponent将会这样做)的面板上没有遗留任何伪像。
@Override
protected void paintComponent(Graphics g) {
g.clearRect(0,0,getWidth(),getHeight());
g.setColor(Color.red);
g.drawLine(0, 0, getWidth(), getHeight());
g.drawLine(getWidth(), 0, 0, getHeight());
}
如果您愿意,请在Hovercrafts代码中尝试此操作。