如何将int转换为24bit字符串？

Question

供我阅读：

def UI24(t):
    result = 0
    for i in xrange(3):
        result = (result << 8);
        byte = unpack('>b',t[i-1])
        result += byte;
    return result

和写作？

Answer 1

更简单地填充它们并作为长期处理

>>> from struct import pack, unpack
>>> def unpack24(s):
...     return unpack(">L","\0"+s)[0]
... 
>>> def pack24(i):
...     return pack(">L",i)[1:]
... 

Answer 2

未经测试！

def UI24back(value):
    result = ""
    for i in xrange(3):
        result = pack('>b', value &255) + result
        value  >>= 8
    return result