Question

过去你们都帮了我很多，我回来寻求更多的帮助！

我正在为学校做另一个C ++作业。我必须从用户那里收集10到100之间的20个数字并将它们全部进行比较并打印出不重复的数字。

我坚持的部分是试图让用户输入循环，直到我有所有20个数字。我对我有意义，但显然不起作用。对于荒谬的评论感到抱歉，我必须为课堂评论一切。

你在我的蠢事上可以流下的任何光线都会令人惊叹！非常感谢你！

int FindDuplicates[20]; // my little array
int UserInput; // the number from the user to compare
int count; // the number of numbers entered

for(count=0; count<FindDuplicates; count++;) // what I am trying to do is have count start at 0. as long as it is less than the max array, add 1 to the count
{
    cout << "Please enter a number between 10 and 100: "; // print out what I would like
    cin >> UserInput; // get the number from the user
}

Answer 1

for( int count = 0; count < 20; count++ )
{
    cout << "Please enter a number between 10 and 100: ";
    cin >> userInput;

    FindDuplicates[ count ] = userInput;
}

您还可以通过以下方式检查有效输入：

while( UserInput < 10 || UserInput > 100 )
{
    cout << "Please enter a number between 10 and 100: ";
    cin >> UserInput;
}

如果您这样做，请确保已将UserInput初始化为某些内容。所以：

int FindDuplicates[ 20 ];
int UserInput = 0;
int count = 0;

//count has already been defined, so no need to do it again
for( ; count < 20; count++ )
{
    //Keep asking until valid input is given
    while( UserInput < 10 || UserInput > 100 )
    {
        cout << "Please enter a number between 10 and 100: ";
        cin >> userInput;
    }

    //Add userInput into the array
    FindDuplicates[ count ] = UserInput;
}

Answer 2

你的问题是如何输入20个有效数字，是吗？我认为do while循环可以帮助你。

int FindDuplicates[20]; // my little array
int UserInput; // the number from the user to compare
int count = 0; // the number of numbers entered

do
{
    cout << "Please enter a number between 10 and 100: "; // print out what I would like
    cin >> UserInput; // get the number from the user

    if (UserInput >= 10 && UserInput <= 100)
    count++;
} while (count < 20);

希望能帮助你。

Answer 3

FindDuplicates将为您提供指向数组的指针（请参阅this），而不是大小。你应该使用

for(count=0; count<20; count++;)

代替。

Answer 4

下面的行有一个语法错误，请检查语句的工作方式。 <FindDuplicates也存在问题。确保您了解该变量的含义。

for(count=0; count<FindDuplicates; count++;)

循环要求用户输入数组

4 个答案: