我有一个名为total的变量，我希望将其转换为时间。
Time from_time = rs.getTime("nfrm_time");
long f = from_time.getTime();
long t= to_time.getTime();
long total= t - f;
那我怎么能这样做？我希望它的格式为HH：MM：SS
答案 0 :(得分：3)
Java竭尽全力使其变得困难，因为请求格式化为默认时区以外的时间非常笨拙。最简单的方法是自己做算术 -
int hours = (int) (total / (60 * 60 * 1000));
int minutes = (int) (total / (60 * 1000)) % 60;
int seconds = (int) (total / 1000) % 60;
或者其他什么东西。 （当然，你会遇到使用前导零格式化列的问题，这是Java中的另一个难题。）
答案 1 :(得分：2)
内置Java库中没有类型来处理持续时间。我建议你使用Joda Time及其Duration类。然后，您可能希望将Duration转换为Period，并使用PeriodFormatter格式化Period。 （根据您的完全要求，您可能希望构建一个Period而不是Duration。）
答案 2 :(得分：1)
Time totalTime = new Time(total)
请参阅Time(long)
答案 3 :(得分：1)
SimpleDateFormat sdf = new SimpleDateFormat("HH:MM:SS");
// Edit: setting the UTC time zone
TimeZone utc = TimeZone.getTimeZone("UTC");
sdf.setTimeZone(utc);
Date date = new Date(total);
System.out.println(sdf.format(date));
答案 4 :(得分：0)
import java.util.Scanner;
public class Time {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("enter offset from GMT: ");
long offset = input.nextLong();
long totalMilliseconds = System.currentTimeMillis();
// NOTE: totalMilliseconds is the number of milliseconds since
// 12am, Jan 1, 1970
System.out.print("enter milliseconds: ");
totalMilliseconds = input.nextLong();
// Given totalMilliseconds and offset, compute hours, minutes, seconds,
// and totalDays, where
// totalDays is the number of days since Jan 1, 1970
// hours, minutes, and seconds is the time of day today.
// All values are adjusted according to the offset from GMT
if (totalMilliseconds < 0) {
System.out.printf("negative time!!\n");
return; // exit program
}
long totalSeconds = totalMilliseconds / 1000;
// System.out.printf("unix time = %d\n", totalSeconds);
long seconds = totalSeconds % 60;
long totalMinutes = totalSeconds / 60;
long minutes = totalMinutes % 60;
long totalHours = totalMinutes / 60;
totalHours += offset;
if (totalHours < 0) {
System.out.printf("negative time!!\n");
return;
}
long hours = totalHours % 24;
long totalDays = totalHours / 24;
// Given totalDays, this computes yearAD, dayInYear, and leapInc, where
// totalDays is the number of days since Jan 1, 1970
// yearAD is the current year
// dayInYear is the day within the current year (in the range 0..364/365)
// leapInc is 1 if yearAD is a leap year and 0 otherwise
long yearAD, dayInYear, leapInc;
long yearOffset = totalDays / 365;
dayInYear = totalDays % 365;
yearAD = 1970 + yearOffset;
long y = yearAD - 1;
long numOfLeapYears =
((y/4) - (1969/4)) -
((y/100) - (1969/100)) + ((y/400) - (1969/400));
dayInYear -= numOfLeapYears;
leapInc = 0;
if (yearAD % 4 == 0 && yearAD % 100 != 0 || yearAD % 400 == 0)
leapInc = 1;
if (dayInYear < 0) {
dayInYear += 365 + leapInc;
yearAD--;
}
if (dayInYear < 0) {
System.out.printf("not implemented!!\n");
return;
}
/* **************** Generate Output ************* */
// Given hours, minutes, and seconds, output current time in friendly AM/PM format
long friendlyHours;
friendlyHours = hours;
if (friendlyHours >= 12)
friendlyHours -= 12;
if (friendlyHours == 0)
friendlyHours = 12;
System.out.printf("%02d:%02d:%02d", friendlyHours, minutes, seconds);
if (hours < 12)
System.out.printf("am");
else
System.out.printf("pm");
System.out.printf(", ");
// given totalDays, output the day of the week (i.e., Sunday, Monday, etc.)
// NOTE: Jan 1, 1970 was a Thursday
long dayOfWeek = totalDays % 7;
if (dayOfWeek == 0)
System.out.printf("Thursday");
else if (dayOfWeek == 1)
System.out.printf("Friday");
else if (dayOfWeek == 2)
System.out.printf("Saturday");
else if (dayOfWeek == 3)
System.out.printf("Sunday");
else if (dayOfWeek == 4)
System.out.printf("Monday");
else if (dayOfWeek == 5)
System.out.printf("Tuesday");
else if (dayOfWeek == 6)
System.out.printf("Wednesday");
System.out.printf(", ");
// Given yearAD, dayInYear, and leapeapInc, output the date in usual format,
// i.e., September 17, 2010
long lower, upper;
upper = 0;
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("January %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 28 + leapInc;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("February %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("March %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 30;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("April %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("May %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 30;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("June %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("July %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("August %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 30;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("September %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("October %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 30;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("November %d, ", dayInYear - lower + 1);
lower = upper;
upper = lower + 31;
if (lower <= dayInYear && dayInYear < upper)
System.out.printf("December %d, ", dayInYear - lower + 1);
System.out.printf("%d", yearAD);
System.out.printf("\n");
}
}
这是我关于整整毫秒的想法