我有三张桌子:
ID_1|..|..| OTHER FIELDS|
ID_2 |..|..|.....
ID_1| ID_2 | SOMEFIELDS|
AND ID_1== ID_2.i.e.
包含所有常见的ids
table 12
包含ids
和table 1
共有的唯一2
。
我正在尝试通过将t1
中的哪些记录与t2
进行匹配来创建一个新表来获取t12
和id_1,id_2
中的所有数据。
以下是我使用的SQL:
CREATE TABLE ARROW_all_common12 AS
SELECT T1.*, T2.* FROM T1, T2
LEFT JOIN T12
ON T12.ID_1=T1.ID_1
LEFT JOIN T12
ON T12.ID_2 = T2.ID_2
WHERE T12.ID2 = T2.ID_2
答案 0 :(得分:2)
我不完全确定你在这里问的是什么,但也许一个观点可能是你在寻找什么?
CREATE VIEW someview AS (
SELECT t1.*, t2.*
FROM table12 AS t12
INNER JOIN table1 AS t1
ON t1.id_1 = t12.id1
INNER JOIN table2 AS t2
ON t12.id_2 = t2.id_2
)
答案 1 :(得分:0)
create table t_all_12 as (
select t1.*, t2.*
from t1, t2, t12
where t12.id_1 = t1.id_1
and t12.id_2 = t1.id_2
)