Question

我一直在尝试使用不同的方法访问NHS API来读取XML。

以下是XML的摘录：

<feed xmlns:s="http://syndication.nhschoices.nhs.uk/services" xmlns="http://www.w3.org/2005/Atom">
 <title type="text">NHS Choices - GP Practices Near Postcode - W1T4LB - Within 5km</title>
 <entry>
  <id>http://v1.syndication.nhschoices.nhs.uk/organisations/gppractices/27369</id>
  <title type="text">Fitzrovia Medical Centre</title>
  <updated>2011-08-20T22:47:39Z</updated>
  <link rel="self" title="Fitzrovia Medical Centre" href="http://v1.syndication.nhschoices.nhs.uk/organisations/gppractices/27369?apikey="/>
  <link rel="alternate" title="Fitzrovia Medical Centre" href="http://www.nhs.uk/ServiceDirectories/Pages/GP.aspx?pid=303A92EF-EC8D-496B-B9CD-E6D836D13BA2"/>
  <content type="application/xml">
   <s:organisationSummary>
    <s:name>Fitzrovia Medical Centre</s:name>
    <s:address>
     <s:addressLine>31 Fitzroy Square</s:addressLine>
     <s:addressLine>London</s:addressLine>
     <s:postcode>W1T6EU</s:postcode>
    </s:address>
    <s:contact type="General">
     <s:telephone>020 7387 5798</s:telephone>
    </s:contact>
    <s:geographicCoordinates>
     <s:northing>182000</s:northing>
     <s:easting>529000</s:easting>
     <s:longitude>-0.140267259415255</s:longitude>
     <s:latitude>51.5224357586293</s:latitude>
    </s:geographicCoordinates>
    <s:Distance>0.360555127546399</s:Distance>
   </s:organisationSummary>
  </content>
 </entry>
</feed>

我一直在使用这个PHP来访问它：

<?php

$feedURL = 'http://v1.syndication.nhschoices.nhs.uk/organisations/gppractices/postcode/W1T4LB.xml?apikey=&range=5';

$raw = file_get_contents($feedURL);

$dom = new DOMDocument();
$dom->loadXML($raw);

$xp = new DOMXPath($dom);
$result = $xp->query("//entry"); // select all entry nodes

print $result->item(0)->nodeValue;

?>

问题是我没有结果，$raw数据存在，但$dom永远不会填充字符串XML。这意味着XPath将无法正常工作。

另外......对于奖励积分：如何在此实例中使用XPath访问<s:Name>标签？

一如既往地感谢帮助。

修改

由于@Andrej L

，以下是生成的PHP工作正常

<?php   

$feedURL = 'http://v1.syndication.nhschoices.nhs.uk/organisations/gppractices/postcode/W1T4LB.xml?apikey=&range=5';
$xml = simplexml_load_file($feedURL);
$xml->registerXPathNamespace('s', 'http://syndication.nhschoices.nhs.uk/services');
$result = $xml->xpath('//s:name');

foreach ($result as $title)
{
    print $title . '<br />';    
}

?>

Answer 1

我认为最好使用SimpleXml库。见http://www.php.net/manual/en/book.simplexml.php
使用http://www.php.net/manual/en/simplexmlelement.registerxpathnamespace.php
使用xpath方法。请参阅http://www.php.net/manual/en/simplexmlelement.xpath.php

在PHP中使用XPath的问题

1 个答案: