Question

我有很多这样的词典：

dict1 = {1:[1,2,3],2:[2,3,4]}
dict2 = {2:[3,4,5],3:[4,5,6]}

我需要

dict = {1:[1,2,3],2:[2,3,4,3,4,5],3:[4,5,6]}
#                       ^
#                       | order is unimportant

这样做的最佳方式是什么？

Answer 1

简单迭代扩展列表......

for key, value in dict2.iteritems():
    dict1.setdefault(key, []).extend(value)

Answer 2

dict1 = {1:[1,2,3],2:[2,3,4]}
dict2 = {2:[3,4,5],3:[4,5,6]}

dicts = [dict1, dict2]
new_dict = {}

for d in dicts:
  for k, v in d.iteritems():
    if new_dict.has_key(k):
      new_dict[k] = new_dict[k] + v
    else:
      new_dict[k] = v

Answer 3

迭代dict2的键;如果dict1中存在相同的密钥，则连接列表并在dict1中设置;否则只需在dict1中设置

Answer 4

a = {'a' : [1,2], 'b' : [3,4]}
b = {'a' : [3,4], 'b' : [1,2]}

for key in a.keys():
    for elem in a[key]:
        b[key].append(elem)

Answer 5

哦，也许有一些聪明的方法可以用reduce来做，但为什么不像普通人一样编写代码。

dict = {}
for each_dict in (dict1, dict2, ...): # ... is not real code
    for key, value in each_dict:
        if not dict.has_key(key):
            dict[key] = []
        dict[key] += value # list append operator

Answer 6

我有很多这样的词典：

通过这种方式，您可以一次“粘合”多个词典：

dict(
  (k, sum((d.get(k, []) for d in dicts), []))
  for k in set(sum((d.keys() for d in dicts), []))
)

通过添加值而不是替换它来更新一个字典与另一个字典

6 个答案: