Question

在下面的函数中，我使用了两个相同的变量，因为里面是不同的语言，我需要帮助来替换这个变量$ periods [$ j]。=“”;

示例：

function showdate($time)  
 {  
 $periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
 $periods2 =   array("seconds", "minutes", "hours", "days", "weeks", "months", "years", "decade");
 $lengths = array("60","60","24","7","4.35","12","10");  

 $now = time();  

 $difference     = $now - $time;  
 $tense         = "ago";  

 for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++)   
     {  
     $difference /= $lengths[$j];  
     }  

 $difference = round($difference);  

 if($difference != 1)   
     {
     **/* In this case i need to show me this variable $periods2 */**  
     $periods[$j].= "";
     }  

 return "$difference $periods[$j] $tense";  
 }

Answer 1

你可以写$periods[$j] = $periods2[$j]，但我认为制作另一个变量更好。

function showdate($time){  
    $periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
    $periods2 = array("seconds", "minutes", "hours", "days", "weeks", "months", "years", "decade");
    $lengths = array("60","60","24","7","4.35","12","10");  

    $now = time();  
    $difference = $now - $time;  
    $tense = "ago";

    for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++)     
        $difference /= $lengths[$j];  

    $difference = round($difference);  
    $pText = $periods[$j];
    if($difference>1) $pText = $periods2[$j];
    return "$difference $pText $tense";  
}

Answer 2

if($difference != 1)   
{
     $periods[$j] = $periods2[$j];
}

此外，您的句点中的十年数组缺少一个s。

时间前帮助

2 个答案: