Question

如何选择字符串值特定的行

SELECT * FROM my_table WHERE name=
   -- then some function to test what string it starts with

有点难以解释所以我将用JavaScript解释一个例子

if(mystring.indexOf('targetstring') != -1){
// if that variable contains this string

}

if(mystring.indexOf('targetstring') == 0){
// if that variable starts with this string

}

总而言之，我想在他们的名字（字符串列）以或包含特定字符串开头时选择行。

Answer 1

您可以使用LIKE和通配符%：

SELECT * FROM my_table WHERE name LIKE 'john%'; /* name starts with john*/ 

SELECT * FROM my_table WHERE name LIKE '%john%'; /* name contains john*/

Answer 2

SELECT * FROM my_table WHERE name like "%string%"

MySQL字符串选择命令

2 个答案: