Question

在sql server中，如何将整数转换为日期和时间，例如：

declare @constant int =92011 or 102011

如何将其转换为日期格式，如“2011年9月”或“2011年10月”。

Answer 1

declare @c int 
set @c = 102011 

;with M(Num, Name) as
(
  select 1,  'January' union all
  select 2,  'February' union all
  select 3,  'March' union all
  select 4,  'April' union all
  select 5,  'May' union all
  select 6,  'June' union all
  select 7,  'Juli' union all
  select 8,  'August' union all
  select 9,  'September' union all
  select 10, 'October' union all
  select 11, 'Novmber' union all
  select 12, 'December'
)
select M.Name+'-'+right(@c, 4)
from M
where M.Num = left(@c, len(@c)-4)

受到DATENAME提供的答案中使用Upendra Chaudhari的启发。

select datename(month, dateadd(month, left(@c, len(@c)-4) - 1, 0))+'-'+right(@c, 4)

Answer 2

试试这个：

declare @c int  
set @c = 92011  
SELECT DATENAME(MONTH,CAST(RIGHT(@c,4) + '-' + LEFT(@C, LEN(@C)-4) + '-01' AS DATE)) + '-' + RIGHT(@c,4)

或以下案例：

declare @c int  
set @c = 92011  
select CASE WHEN LEFT(@C, LEN(@C)-4) = 1 THEN 'January' 
      WHEN LEFT(@C, LEN(@C)-4) = 2 THEN 'February' 
      WHEN LEFT(@C, LEN(@C)-4) = 3 THEN 'March' 
      WHEN LEFT(@C, LEN(@C)-4) = 4 THEN 'April' 
      WHEN LEFT(@C, LEN(@C)-4) = 5 THEN 'May' 
      WHEN LEFT(@C, LEN(@C)-4) = 6 THEN 'June' 
      WHEN LEFT(@C, LEN(@C)-4) = 7 THEN 'July' 
      WHEN LEFT(@C, LEN(@C)-4) = 8 THEN 'August' 
      WHEN LEFT(@C, LEN(@C)-4) = 09 THEN 'September' 
      WHEN LEFT(@C, LEN(@C)-4) = 10 THEN 'October' 
      WHEN LEFT(@C, LEN(@C)-4) = 11 THEN 'November' 
      WHEN LEFT(@C, LEN(@C)-4) = 12 THEN 'December' 
      ELSE '' END + '-' + RIGHT(@c,4)

将整数转换为日期和时间格式？

2 个答案: