Question

我是PHP正则表达式的新手，我读了http://php.net/manual/en/function.preg-match.php。但找不到修复我的bug的方法。你能帮我个忙吗？感谢。

<?php

$myURL = "/something/";  
// If myURL include two or more than two '/' then return Found, Else return Not found two '/'

if (preg_match("/\/?\//", $myURL)) {
    echo "found";
} else {
    echo "not found";
}
?>

Answer 1

我建议使用substr_count。

$numSlashes = substr_count($text, '/');

晒。

Answer 2

<?php

$myURL = "/something/";  
// If myURL include two or more than two '/' then return Found, Else return Not found two '/'

if (preg_match("/\/.*\//", $myURL)) {
    echo "found";
} else {
    echo "not found";
}
?>

Answer 3

如果你想以正则表达式方式去：

$myURL = "/some//thing/";  


if (array_search("//", preg_match_all("/\/?\//", $myURL))) {
    echo "found";
} else {
    echo "not found";
}
?>

关于PHP正则表达式的问题

3 个答案: