Question

如何将拆分管道将SQL中的字符串值分隔为单独的列，例如

2008 | 1245 | 0 | 1004 | 1224 | 0 |

到

FirstValue SecondValue ThirdValue   ForthValue   FifthValue    SixthValue
2008       1245        0            1004         1224         0

使用简单的选择脚本。

谢谢

Answer 1

试试

CREATE FUNCTION dbo.fnSplit(
    @sInputList VARCHAR(8000) -- List of delimited items
  , @sDelimiter VARCHAR(8000) = '|' -- delimiter that separates items
) RETURNS @List TABLE (item VARCHAR(8000))

BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
 BEGIN
 SELECT
  @sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
  @sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))

 IF LEN(@sItem) > 0
  INSERT INTO @List SELECT @sItem
 END

IF LEN(@sInputList) > 0
 INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
GO
--Test
select * from fnSplit('2008|1245|0|1004|1224|0|','|')

SQL 2008 - 管道分隔的字符串拆分

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