Question

我有一个listView，想要长按显示我的自定义对话框。我怎么这么做？我所有的尝试都没有带给我任何东西对话框从不显示，ANR发生。

 @Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) menuInfo;
    int type = ExpandableListView.getPackedPositionType(info.packedPosition);
    int group = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int child = ExpandableListView.getPackedPositionChild(info.packedPosition);

    if (type == 1) {
        menu.add("rating");

    }
}


@Override
public boolean onContextItemSelected(MenuItem menuItem) {
    Handler handler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            int rating = msg.arg1;
            System.out.println("Rating  = " + rating);
        }
    };
    System.out.println("Create rating dialog");
    Toast.makeText(MyListActivity.this, "Ass", Toast.LENGTH_SHORT).show();
   // new RatingDialog(MyListActivity.this, handler).show();

    return super.onContextItemSelected(menuItem);

}

评级对话框从不显示，吐司效果很好。有必要显示上下文菜单，或者我可以从onCreateContextMenu（）启动我的对话框吗？

谢谢！

Answer 1

您可能需要在对话框之前显示上下文菜单。然后，您可以选择评分。

Android系统。从上下文菜单启动对话框

1 个答案: