Question

我试图将天气预报功能的结果放在PHP返回语句中。要使用连接来执行此操作，我需要在代码中移动foreach循环，我无法使其工作。

我正在尝试创建这样的函数::

function getWeatherForecast($atts) {
    all variables go here;
    return 'concatenated output';
}

这是指向完整脚本的链接：http://pastebin.com/fcQpskmy

这就是我现在所拥有的：

function getWeatherForecast($atts) {
    $xml = simplexml_load_file('http://www.google.com/ig/api?weather=barcelona');
    $information = $xml->xpath("/xml_api_reply/weather/forecast_information");
    $current = $xml->xpath("/xml_api_reply/weather/current_conditions");
    $forecast_list = $xml->xpath("/xml_api_reply/weather/forecast_conditions");

    /* The foreach loop should go here */

    return '<h2>The weather today ' . $information[0]->city['data'] . '</h2>';
    /* etc. etc. */
}

这是我需要在return语句之前放置的foreach循环：

<?php foreach ($forecast_list as $forecast) : ?>
<div>
    <img src="<?php echo 'http://www.google.com' . $forecast->icon['data']?>" alt="weather"?>
    <div><?php echo $forecast->day_of_week['data']; ?></div>
    <span>
    <?php echo $forecast->low['data'] ?>&deg; F – <?php echo $forecast->high['data'] ?>&deg; F,
    <?php echo $forecast->condition['data'] ?>
    </span>    
</div>
<?php endforeach ?>

非常感谢你的帮助!!

Answer 1

我们很清楚，你希望foreach能够在函数内部吗？

在那种情况下：

 $html_code = "";
 foreach ($forecast_list as $forecast) {
     $html_code .='<div>
          <img src="http://www.google.com' . $forecast->icon['data']. '" alt="weather" />
          <div>'.$forecast->day_of_week['data'].'</div>
          <span>
              '. $forecast->low['data'] .'&deg; F – '. $forecast->high['data'] .'&deg; F,
            '. $forecast->condition['data'] .'
         </span>    
         </div>
  }

然后$ html_code将需要在return语句中连接所有html代码。

这是你需要的吗？

Answer 2

我试过这个并且有效：

<?
    echo getWeatherForecast('');
    function getWeatherForecast($atts) {
        $xml = simplexml_load_file('http://www.google.com/ig/api?weather=barcelona');
        $information = $xml->xpath("/xml_api_reply/weather/forecast_information");
        $current = $xml->xpath("/xml_api_reply/weather/current_conditions");
        $forecast_list = $xml->xpath("/xml_api_reply/weather/forecast_conditions");
        foreach ($forecast_list as $forecast) { 
?>
    <div>
        <img src="<?php echo 'http://www.google.com' . $forecast->icon['data']?>" alt="weather"?>
        <div><?php echo $forecast->day_of_week['data']; ?></div>
        <span>
            <?php echo $forecast->low['data'] ?>&deg; F – <?php echo $forecast->high['data'] ?>&deg; F,
            <?php echo $forecast->condition['data'] ?>
        </span>    
    </div>
<?  }

    return '<h2>The weather today ' . $information[0]->city['data'] . '</h2>';
    /* etc. etc. */
    }
?>

但这不是正确的方法。使用一个变量来累积html，然后返回所有的html。像这样：

<?
    echo getWeatherForecast('');
    function getWeatherForecast($atts) {
        $xml = simplexml_load_file('http://www.google.com/ig/api?weather=barcelona');
        $information = $xml->xpath("/xml_api_reply/weather/forecast_information");
        $current = $xml->xpath("/xml_api_reply/weather/current_conditions");
        $forecast_list = $xml->xpath("/xml_api_reply/weather/forecast_conditions");
        $html = '';
        foreach ($forecast_list as $forecast) {
            $html .= '<div>';
            $html .=  '<img src="http://www.google.com'.$forecast->icon['data'].'" alt="weather"/>';
            $html .=  '<div>'.$forecast->day_of_week['data'].'</div>';
            $html .=  '<span>';
            $html .=  $forecast->low['data'].'&deg; F – '.$forecast->high['data'].'&deg; F,'.$forecast->condition['data'];
            $html .=  '</span>';
            $html .= '</div>';
        }
        $html .= '<h2>The weather today ' . $information[0]->city['data'] . '</h2>'

        return $html;
        /* etc. etc. */
    }
?>

在return语句之前移动foreach循环

2 个答案: