Question

我在下面的代码中遗漏了什么？我有点不知所措。

$("a[id^='submitspam']").click(function () { 
    var thisForm = $(this).attr('id');
    var com_id = $(this).attr('id').substring(11);
    var thisFormFull = '#' + thisForm;

    $.ajax({  
        type: "POST",
        url: "/songs/spam.php",
        data: "command=mark_spam&cid=" + com_id,

        complete: function(data){
            messageList = 'contentspam-' + com_id;
            $('span#' + messageList).html(data.responseText);
            $(thisFormFull).hide();
            $('span#' + messageList).fadeIn();
        }
    });

    return false;  
});

Answer 1

适合我。我使用您的代码创建了jsfiddle，然后单击IE 8中的链接会生成一个请求。我使用Fiddler来检查HTTP请求：

POST /songs/spam.php HTTP/1.1
x-requested-with: XMLHttpRequest
Accept-Language: en-US,en;q=0.7,es;q=0.3
Referer: http://fiddle.jshell.net/josh3736/Ghy5C/show/
Accept: */*
Content-Type: application/x-www-form-urlencoded
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; WOW64; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; Zune 4.0; .NET CLR 1.1.4322; .NET4.0C; InfoPath.3)
Host: fiddle.jshell.net
Content-Length: 23
Connection: Keep-Alive
Pragma: no-cache

command=mark_spam&cid=1

即使AJAX请求404s（jsfiddle的服务器上没有spam.php），链接也会在请求完成后隐藏。顺便说一下，你应该使你的回调函数成为success回调而不是complete回调，这样你的UI就不会报告操作成功，而实际上是有错误。

为什么AJAX不能在IE中运行？

1 个答案: