Question

我有一个名为CHCID的类，里面有两个函数：

public function UpdateDeliveryAddress($orderNumber, $deliveryaddress) {

    $sql = "UPDATE `CIDOrders`

    SET `DeliveryAddress` = '" . mysql_real_escape_string($deliveryaddress) . "'

    WHERE `CIDOrderNumber` = " . $orderNumber . ";";

    mysql_select_db(DB_DATABASE_NAME, $this->conn);

    return mysql_query($sql, $this->conn);

}

public function UpdateInvoiceAddress($orderNumber, $invoiceAddress) {

    $sql = "UPDATE `CIDOrders`

    SET `InvoiceAddress` = '" . mysql_real_escape_string($invoiceaddress) . "'

    WHERE `CIDOrderNumber` = " . $orderNumber . ";";

    mysql_select_db(DB_DATABASE_NAME, $this->conn);

    return mysql_query($sql, $this->conn);

}

我在名为createorder.php的页面中调用此类，如下所示：

// Add a new delivery address to the order

$cid->UpdateDeliveryAddress($_POST['orderNumber'], $_POST['deliveryaddress']);

// Add invoice address to the order

$cid->UpdateInvoiceAddress($_POST['orderNumber'], $_POST['invoiceaddress']);

我收到以下错误：

PHP Fatal error:  Call to undefined method CHCID::UpdateDeliveryAddress()

任何人都可以提供帮助。

非常感谢

代码初始化类。

require_once $CID_INCLUDE_PATH . "/cid.php";

$cid = new CHCID();

构建类

class CHCID {



    var $conn;



    // Constructor, connect to the database

    public function __construct() {

        require_once "/var/www/reporting/settings.php";

        if(!$this->conn = mysql_connect(DB_HOST, DB_USERNAME, DB_PASSWORD)) die(mysql_error());

        if(!mysql_select_db(DB_DATABASE_NAME, $this->conn)) die(mysql_error());

    }

Answer 1

如果这些功能真的在你的课堂上，那么这种情况永远不会发生。

检查$CID_INCLUDE_PATH，你可能正在加载一个不同的文件，也许是该类的旧版本。同时启用警告，通知......

调用未定义的方法php错误

1 个答案: