CXF - JAX-WS服务器端模式验证未找到元素定义

时间:2011-09-30 12:51:33

标签: web-services jaxb jax-ws cxf

我有一个Web服务,它在webTypes部分定义了几个模式。我定义了一个read操作,该类型在此模式中定义:

<xs:schema version="1.0" targetNamespace="http://example.com/webservice/service" xmlns:ns0="http://example.com/webservice/parameter" xmlns:xs="http://www.w3.org/2001/XMLSchema">
     <xs:import namespace="http://example.com/webservice/parameter"/>
     <xs:complexType name="read">
        <xs:sequence>
           <xs:element name="name" type="xs:string" minOccurs="1" maxOccurs="1" />
           <xs:element name="filter" type="ns0:filter" minOccurs="0" maxOccurs="1"/>
           <xs:element name="startIndex" type="xs:int" minOccurs="1" maxOccurs="1" />
           <xs:element name="noOfResults" type="xs:int" minOccurs="1" maxOccurs="1" />
        </xs:sequence>
     </xs:complexType>
     <xs:element name="read" type="tns:read"/>
  </xs:schema>

然后我在CXF配置文件中激活架构验证,如下所示:

<jaxws:endpoint id="dataService" 
                implementor="com.example.webservice.jaxws.endpoint.SIB"
                address="/DataService"
                wsdlLocation="classpath:DataService.wsdl">
                <jaxws:properties>
                    <entry key="schema-validation-enabled" value="true" />
                </jaxws:properties>
</jaxws:endpoint>

我测试了我的模式,用SOAPUI验证器验证了我的一些请求,它运行得很好。但在服务器端,当收到请求时,我收到此错误:

Caused by: javax.xml.bind.UnmarshalException
  - with linked exception:
 [org.xml.sax.SAXParseException: cvc-elt.1: Cannot find the declaration of element 'name'.]
     at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.handleStreamException(UnmarshallerImpl.java:425)
     at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:362)
     at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:339)
     at org.apache.cxf.jaxb.JAXBEncoderDecoder.unmarshall(JAXBEncoderDecoder.java:768)
     ... 287 more
Caused by: org.xml.sax.SAXParseException: cvc-elt.1: Cannot find the declaration of element 'name'.
     at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
     at org.apache.xerces.util.ErrorHandlerWrapper.error(Unknown Source)
     at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
     at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
     at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
     at org.apache.xerces.impl.xs.XMLSchemaValidator.handleStartElement(Unknown Source)
     at org.apache.xerces.impl.xs.XMLSchemaValidator.startElement(Unknown Source)
     at org.apache.xerces.jaxp.validation.ValidatorHandlerImpl.startElement(Unknown Source)
     at com.sun.xml.bind.v2.runtime.unmarshaller.ValidatingUnmarshaller.startElement(ValidatingUnmarshaller.java:96)
     at com.sun.xml.bind.v2.runtime.unmarshaller.StAXStreamConnector.handleStartElement(StAXStreamConnector.java:242)
     at com.sun.xml.bind.v2.runtime.unmarshaller.StAXStreamConnector.bridge(StAXStreamConnector.java:176)
     at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:360)
     ... 289 more

任何线索?似乎验证器可以访问“读取”操作定义。我不知道该怎么做,因为实际上webservices在没有模式验证的情况下正常工作,但我想避免在Web服务实现中进行param验证。

提前致谢,

注意我正在使用带有JAXWS 2.2的CXF 2.3.3和带有java 1.6.0的非认可tomcat 6中的JAXB 2.2.1。

0 个答案:

没有答案