Question

我正在尝试根据LIKE通配符过滤搜索结果。如果最终用户输入多个关键字，我还想添加几个OR语句。但我的查询返回所有结果而不是过滤结果，下面是代码

        function search()
        {
            $queries = explode(" ", $this->data['Project']['query']);
            $nq = '';
            foreach($queries as $q)
            {
                $nq[] = array('Project.project_title LIKE'=>"%$q%");
            }

            $final = array("OR"=>$nq);

            debug($this->Project->find('list',$final));
        }



1   SHOW FULL COLUMNS FROM `projects`       28  28  16
2   SELECT CHARACTER_SET_NAME FROM INFORMATION_SCHEMA.COLLATIONS WHERE COLLATION_NAME= 'latin1_swedish_ci';     1   1   1
3   SHOW FULL COLUMNS FROM `users`      2   2   8
4   SELECT CHARACTER_SET_NAME FROM INFORMATION_SCHEMA.COLLATIONS WHERE COLLATION_NAME= 'utf8_general_ci';       1   1   1
5   SHOW FULL COLUMNS FROM `categories`     6   6   11
6   SHOW FULL COLUMNS FROM `operating_systems`      2   2   7
7   SHOW FULL COLUMNS FROM `project_operating_systems`      3   3   10
8   SHOW FULL COLUMNS FROM `projects_categories`        3   3   12
9   SELECT `Project`.`id`, `Project`.`project_title` FROM `projects` AS `Project` WHERE 1 = 1       4   4   1
10  SELECT `Category`.`id`, `Category`.`name`, `Category`.`parent_id`, `Category`.`url`, `Category`.`lft`, `Category`.`rght`, `ParentCategory`.`id`, `ParentCategory`.`name`, `ParentCategory`.`parent_id`, `ParentCategory`.`url`, `ParentCategory`.`lft`, `ParentCategory`.`rght` FROM `categories` AS `Category` LEFT JOIN `categories` AS `ParentCategory` ON (`Category`.`parent_id` = `ParentCategory`.`id`) WHERE 1 = 1

Answer 1

debug($this->Project->find('list',array('conditions'=>$final)));

Answer 2

在构建一系列or这样的查询时，请务必将OR条件括在括号中，否则您将否定AND条件。

示例：

SELECT * 
FROM users
WHERE type='teacher'

只给你老师。

SELECT * 
FROM users
WHERE type='teacher'
AND name like '%Joe%'

这只会让教师在名字的某个地方加上“Joe”。但是：

SELECT * 
FROM users
WHERE type='teacher'
AND name like '%Joe%'
OR name like '%Mary%'

你可能希望这能给那些名字叫“Joe”或“Mary”的老师......但事实并非如此。它将为您提供名称为“Mary”的任何用户。要更正此问题，请使用括号：

SELECT * 
FROM users
WHERE type='teacher'
AND 
(name like '%Joe%'
OR name like '%Mary%')

CAKEPHP条件或声明

2 个答案: