Question

我有listbox1绑定到名为DataTable的{{1}}，我在DataTable的单元格中设置值的行更改Notes然后再设置listBox1.SelectedIndex = -1 1}}到原始值并完成。因此该行调用listBox1.SelectedIndex事件两次。

相反，它甚至不应该调用该事件。如何解决这个问题？

listBox1_SelectedIndexChanged

Answer 1

暂时删除SelectedIndexChanged处理程序

private void richTextBox1_TextChanged(object sender, EventArgs e)
{
  listBox1.SelectedIndexChanged -= listBox1_SelectedIndexChanged;
  if (listBox1.SelectedIndex != -1)
  {
      dataSet11.Notes.Rows[listBox1.SelectedIndex]["Text"] = richTextBox1.Text; 
      //this line fires listBox1_SelectedIndexChanged event
      //with listBox1.SelectedIndex = -1
      //then it changes listBox1.SelectedIndex back to original value before complete execution, and calls the even again
  }
  listBox1.SelectedIndexChanged += listBox1_SelectedIndexChanged;
}

Answer 2

您可以使用触发器布尔字段：

private TextBox_OntextChanged(object sender, EventArgs args)
{
    this.supressEvents = true;
    //Do your stuff here
    this.supressEvents = false;
}

private void ListBox_OnSelectionChanged(object sender, EventArgs args)
{
    if (this.supressEvents)
    {
        return;
    }

    //Do your stuff here
}

在DataTable中设置值会触发SelectedIndexChanged事件

2 个答案: