Question

开发，

我是透视表的新手，并且在重复时遇到了一些问题。我的表，在旋转之前看起来像这样：

以下是pivot的代码，工作正常：

SELECT PivotTable.location, [apple], [orange], [pear]
FROM
(SELECT location, food FROM someTable) as inventory
PIVOT
(COUNT(inventory.food) FOR inventory.location IN ([apple],[orange],[pear])) AS PivotTable

这会产生如下输出：

位置 | Apple | 橙色 |的梨
田纳西州| 0 | 1 | 1
佛罗里达| 1 | 1 | 0
弗吉尼亚| 0 | 0 | 1

正如我所说，工作正常。但是，我在原始表中添加了新的注释列，如下所示：

位置 | 食物 | apple_comments | orange_comments |的 pear_comments

以下是我更改的数据透视表以说明评论：

SELECT PivotTable.location, [apple], [apple_comments], [orange], [orange_comments], [pear], [pear_comments]
FROM
(SELECT location, food, apple_comments, orange_comments, pear_comments FROM someTable) as inventory
PIVOT
(COUNT(inventory.food) FOR inventory.location IN ([apple],[orange],[pear])) AS PivotTable

这会产生如下输出：

位置 | Apple | apple_comments | 橙色 | Orange_comments | 梨 |的 Pear_comments
田纳西州| 0 | NULL | 0 | NULL | 1 | NULL
田纳西州| 0 | NULL | 1 |很多汁0 | NULL
佛罗里达| 0 | NULL | 1 | NULL | 0 | NULL
佛罗里达| 1 |脆| 1 | NULL | 0 | NULL
弗吉尼亚| 0 | NULL | 1 | NULL | 1 |可口

因此，基本上，当为每个有多个位置的条目添加注释时，它会创建一个重复的行。在弗吉尼亚州的情况下，只有一个条目，所以行结果很好。

似乎我需要做另一个支点或其他什么。任何人都可以就我出错的地方提供建议吗？

对不起。所需的输出应如下所示：

位置 | Apple | apple_comments | 橙色 | Orange_comments | 梨 |的 Pear_comments
田纳西州| 0 | NULL | 1 |很多汁1 | NULL
佛罗里达| 1 |脆| 1 | NULL | 0 | NULL
弗吉尼亚| 0 | NULL | 1 | NULL | 1 |可口

基本上，将重复项合并为一行。

感谢。

Answer 1

根本问题在于，除了comment列之外，您已经有效地告诉编译器按food列进行分组。有一些解决方案，例如将注释汇总到分隔列表中，如下所示：

Select location
    , Sum( Case When S.food = 'Apple' Then 1 Else 0 End ) As Apple
    , Stuff(
        (
        Select ', ' + S1.Apple_Comments
        From SomeTable As S1
        Where S1.location = S.location
            And S1.Apple_Comments Is Not Null
        Group By S1.Apple_Comments
        For Xml Path(''), type
        ).value('.','nvarchar(max)')
        , 1, 2, '') As Apple_Comments
    , Sum( Case When S.food = 'Orange' Then 1 Else 0 End ) As Orange
    , Stuff(
        (
        Select ', ' + S1.Orange_Comments
        From SomeTable As S1
        Where S1.location = S.location
            And S1.Orange_Comments Is Not Null
        Group By S1.Orange_Comments
        For Xml Path(''), type
        ).value('.','nvarchar(max)')
        , 1, 2, '') As Orange_Comments
    , Sum( Case When S.food = 'Pear' Then 1 Else 0 End ) As Pear
    , Stuff(
        (
        Select ', ' + S1.Pear_Comments
        From SomeTable As S1
        Where S1.location = S.location
            And S1.Pear_Comments Is Not Null
        Group By S1.Pear_Comments
        For Xml Path(''), type
        ).value('.','nvarchar(max)')
        , 1, 2, '') As Pear_Comments
From SomeTable As S
Group By S.location

Answer 2

找到答案（利用'with CTE'和MAX函数）：

;With CTE as (
SELECT PivotTable.location, [apple], [apple_comments], [orange], [orange_comments], [pear], [pear_comments]
FROM
(SELECT location, food, apple_comments, orange_comments, pear_comments FROM someTable) as inventory
PIVOT
(COUNT(inventory.food) FOR inventory.location IN ([apple],[orange],[pear])) AS PivotTable)
select location, MAX([apple]) as [apple], MAX([apple_comments]) as [apple_comments],MAX([orange]) as [orange], 
MAX([orange_comments]) as [orange_comments], MAX([pear]) as [pear], MAX([pear_comments]) as [pear_comments]
from CTE group by location

SQL数据透视表生成重复项

2 个答案: