-(id)init{
if (self==[super init]) {
NSMutableArray *listname = [[NSMutableArray alloc]initWithObjects:@"cu",@"al",@"zn",@"au",@"ru",@"fu",@"rb",@"pb",@"wr", nil];
NSMutableArray *listVolumn = [NSMutableArray arrayWithCapacity:[listname count]];
for (int i=0; i<[listname count]; i++) {
[listVolumn addObject:[NSNumber numberWithLong:0]];
}
nsmutabledictionary = [[NSDictionary alloc] initWithObjects:listVolumn forKeys:listname];
}
return self;
}
在我的init方法中,我定义了两个NSMutableArray,并添加到NSMutableDictionary nsmutabledictionary。 用我的另一种方法:
[nsmutabledictionary setObject:[NSNumber numberWithLong:100] forKey:@"cu"];
但它在上面线崩溃:
答案 0 :(得分:16)
nsmutabledictionary = [[NSDictionary alloc] initWithObjects:listVolumn forKeys:listname];
应该是
nsmutabledictionary = [[NSMutableDictionary alloc] initWithObjects:listVolumn forKeys:listname];
答案 1 :(得分:2)
在您的代码中,我看到nsmutabledictionary = [[NSDictionary alloc] initWithObjects:listVolumn forKeys:listname];
当你打算将它作为NSMutableDictionary