Question

我以非常难以使用的格式从API中获取数据（在需要使用的mannor中） - 我无法修改API。以下是我给出的数据示例：

    $data = array(
        array('day' => 'Monday', 'start' => 1100, 'end' => 1300),
        array('day' => 'Tuesday', 'start' => 1100, 'end' => 1300),
        array('day' => 'Wednesday', 'start' => 1100, 'end' => 1300),
        array('day' => 'Thursday', 'start' => 1200, 'end' => 1300),
        array('day' => 'Friday', 'start' => 1200, 'end' => 1300),
        array('day' => 'Saturday', 'start' => 1200, 'end' => 1300),
        array('day' => 'Sunday', 'start' => 1200, 'end' => 1400)
    );

数据可能不包括一周中的所有七天，开始和结束在0000和2400之间变化。我试图想出一种方法来使用以下输出格式化数据：Monday - Wednesday (1100-1300), Thursday - Saturday (1200-1300), Sunday (1200-1400)基本上，连续天（其开始和结束时间相同）由一个超级分开。

我有点想避免一大堆难看的代码

Answer 1

丑陋是旁观者的眼睛。 ;）我认为这是可以的，但当然它可能正是你想要避免的。

<?php
$data = array(
    array('day' => 'Monday', 'start' => 1100, 'end' => 1300),
    array('day' => 'Tuesday', 'start' => 1100, 'end' => 1300),
    array('day' => 'Wednesday', 'start' => 1100, 'end' => 1300),
    array('day' => 'Thursday', 'start' => 1200, 'end' => 1300),
    array('day' => 'Friday', 'start' => 1200, 'end' => 1300),
    array('day' => 'Saturday', 'start' => 1200, 'end' => 1300),
    array('day' => 'Sunday', 'start' => 1200, 'end' => 1400)
);

$periods = array();

$start = $end = $i = -1;

foreach ($data as $datum) {
    if ($start != $datum['start'] || $end != $datum['end']) {
        $i++;
        $start = $datum['start'];
        $end   = $datum['end'];

        $periods[$i] = array(
                          'start'    => $start, 
                          'end'      => $end,
                          'startDay' => $datum['day']);
    }
    $periods[$i]['endDay'] = $datum['day'];
}

foreach ($periods as $k => $period) {
    echo ($k) ? ', ' : '';
    if ($period['startDay'] === $period['endDay']) {
        echo $period['startDay'];
    } else {
        echo "{$period['startDay']} - {$period['endDay']}";
    }
    echo " ({$period['start']} - {$period['end']})";
}

输出：

Monday - Wednesday (1100 - 1300), Thursday - Saturday (1200 - 1300), Sunday (1200 - 1400)

Answer 2

我的解决方案：

function data_to_array(&$data, $cols) {
  foreach($data as &$value) {
    $value = array_combine($cols, explode(',', $value));
  }
}

$data = Array(
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400',
  'Monday,1200,1400'
);

data_to_array($data, Array('day','start','end'));
// now $data is again ugly block of data :)

现在您可以将其保存在文本文件中的 data.txt中：

Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400 Monday,1200,1400

你的php文件：

$data = explode("\n", file_get_contents('data.txt')); data_to_array($data, Array('day','start','end')); // now $data is again ugly block of data :)

格式化数据很好

2 个答案: