Question

private Magazine[,] [] myMags;

我正在尝试使用包含2D杂志[14,14]的1d数组（长度为5）。所以我可以去（即1d数组中的每个元素引用一个带有14x14（= 196个杂志）的2d数组）：

myMags[0] = new Magazine[14,14];
myMags[1] = new Magazine[14,14];
myMags[2] = new Magazine[14,14];
myMags[3] = new Magazine[14,14];
myMags[4] = new Magazine[14,14];

以这种方式初始化和分配元素的正确语法是什么？

Answer 1

    Magazine[][,] myMags = new Magazine[5][,];
    myMags[0] = new Magazine[14, 14];
    myMags[1] = new Magazine[14, 14];
    myMags[2] = new Magazine[14, 14];
    myMags[3] = new Magazine[14, 14];
    myMags[4] = new Magazine[14, 14];

Answer 2

我相信这会有用

   private Magazine[,,] myVarName = new Magazine[4,14,14];

参考http://msdn.microsoft.com/en-us/library/2yd9wwz4(v=VS.100).aspx

2d数组的锯齿状数组

2 个答案: