MySQL查询帮助

时间:2011-10-23 01:32:07

标签: mysql sql pivot

以下是我正在使用的表格的说明:

describe mjla_db.StudentRecordTable2;
+-----------+-------------+------+-----+---------+-------+
| Field     | Type        | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+-------+
| classId   | varchar(20) | NO   | MUL | NULL    |       |
| studentId | varchar(20) | NO   | MUL | NULL    |       |
| quizGrade | tinyint(4)  | YES  |     | NULL    |       |
| quizId    | int(11)     | NO   | MUL | NULL    |       |
+-----------+-------------+------+-----+---------+-------+
4 rows in set (0.00 sec)

以下是数据库中的示例数据:

+------------+-----------+------------+---------+------------+
| Student ID | Last Name | First Name | Quiz ID | Quiz Grade |
+------------+-----------+------------+---------+------------+
| A1         | Cat       | Tom        |      19 |       75   |
| A2         | pancake   | Harry      |      19 |       65   |
| A5         | Worthy    | Dick       |      19 |       NULL |
| A1         | Cat       | Tom        |      20 |       55   |
| A2         | pancake   | Harry      |      21 |       NULL |
| A2         | pancake   | Harry      |      20 |       47   |
| A5         | Worthy    | Dick       |      20 |       95   |
| A1         | Cat       | Tom        |      21 |       55   |
| A5         | Worthy    | Dick       |      21 |       95   |
+------------+-----------+------------+---------+------------+
3 rows in set (0.00 sec)

我想要得到的结果是类似于以下内容的结果:

+------------+-----------+------------+---------+------------+------------+
| Student ID | Last Name | First Name | Quiz 19 | Quiz 20    | Quiz 21    |
+------------+-----------+------------+---------+------------+------------+
| A1         | Cat       | Tom        |      75 |       55   |       55   |
| A2         | pancake   | Harry      |      65 |       47   |       NULL |
| A5         | Worthy    | Dick       |     NULL|       95   |       95   |
+------------+-----------+------------+---------+------------+------------+
  • 学生ID列唯一。
  • 测验栏的位置取决于测验的数量 原表。测验列包含每个的等级 各自的学生。

1 个答案:

答案 0 :(得分:3)

试试这个:

 select s.StudentId, s.FirstName, s.LastName, 
 Case when s.QuizId = 19 then quizGrade end as 'Quiz 19',
 Case when s.QuizId = 20 then quizGrade end as 'Quiz 20',
 Case when s.QuizId = 21 then quizGrade end as 'Quiz 21'
 from StudentRecordTable2 sr 
 inner join Students s on sr.StudentId = s.StudentId

请参阅this

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