SCALA Lift - 扩展功能的缺失参数类型

时间:2011-10-25 14:31:46

标签: ajax scala lift

我有以下表格:

<form class="lift:form.ajax">

    <div class="lift:StreamInput">
        <input type="hidden" name="user" value="USER" />
        <input type="hidden" name="room" value="ROOM" />
        <input type="hidden" name="path" value="PATH" />
        <input type="hidden" name="level" value="LEVEL" />
    </div>

    <input type="submit" value="" />

</form>

进入:

object StreamInput {

    case class StreamItem(

        user: String, 
        path: String, 
        level: String, 
        room: String

    )

    def render = {

        var user = ""
        var path = ""
        var level = ""
        var room = ""

        def process(): JsCmd = {

            var message = StreamItem(user, path, level, room)
            StreamServer ! message

        }

        "name=user" #> SHtml.onSubmit(user => user = _)
        "name=path" #> SHtml.onSubmit(path => path = _)
        "name=level" #> SHtml.onSubmit(level => level = _)
        "name=room" #> (SHtml.onSubmit(room => room = _) ++ SHtml.hidden(process))

    }

}

编译时我遇到以下错误:

"Missing parameter type for expanded function ((x$1) => user = x$1)"
"name=user" #> SHtml.onSubmit(user => user = _)
                                             ^
"Missing parameter type for expanded function ((x$2) => user = x$2)"
"name=path" #> SHtml.onSubmit(path => path = _)
                                             ^
"Missing parameter type for expanded function ((x$3) => user = x$3)"
"name=level" #> SHtml.onSubmit(level => level = _)
                                                ^
"Missing parameter type for expanded function ((x$4) => user = x$4)"
"name=room" #> SHtml.onSubmit(room => room = _)
                                             ^

我一直在谷歌搜索一段时间,似乎无法找到适合我特定情况的解释。

不确定我缺少什么,非常感谢任何帮助,提前谢谢:)

1 个答案:

答案 0 :(得分:0)

SHtml.onSubmit需要回调(String) ⇒ AnyString是新提交的字段值。在您的情况下,您希望提供一个setter方法,将var更改为该新值。将参数更改为

SHtml.onSubmit(user = _)

或扩展

SHtml.onSubmit(text => user = text)

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