获取数据库中所有表的大小

时间:2011-10-25 16:14:34

标签: sql-server tsql

我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎占用了比我预期更多的空间。

是否有一种简单的方法可以确定每个表占用的磁盘空间大小?

25 个答案:

答案 0 :(得分:2239)

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    t.Name

答案 1 :(得分:491)

如果您使用的是 SQL Server Management Studio (SSMS),而不是运行查询(,在我的情况下返回重复的行),您可以运行标准报告

  1. 右键单击数据库
  2. 导航至报告>标准报告>表格中的磁盘使用情况
  3. 注意:必须将数据库兼容级别设置为90或更高才能使其正常工作。见http://msdn.microsoft.com/en-gb/library/bb510680.aspx

答案 2 :(得分:93)

sp_spaceused可以获取有关表,索引视图或整个数据库使用的磁盘空间的信息。

例如:

USE MyDatabase; GO

EXEC sp_spaceused N'User.ContactInfo'; GO

报告ContactInfo表的磁盘使用信息。

一次性将它用于所有表格:

USE MyDatabase; GO

sp_msforeachtable 'EXEC sp_spaceused [?]' GO

您还可以从右键单击SQL Server的标准报告功能中获取磁盘使用情况。要获取此报告,请从对象资源管理器中的服务器对象导航,向下移动到Databases对象,然后右键单击任何数据库。从显示的菜单中,选择“报告”,然后选择“标准报告”,然后选择“按分区的磁盘使用情况:[DatabaseName]”。

答案 3 :(得分:36)

以下是另一种方法:使用 SQL Server Management Studio ,在对象资源管理器中,转到您的数据库并选择

enter image description here

然后打开对象资源管理器详细信息(通过按 F7 或转到 View->对象资源管理器详细信息)。在对象资源管理器详细信息页面中,右键单击列标题并启用您希望在页面中看到的列。您也可以按任何列对数据进行排序。

enter image description here

答案 4 :(得分:35)

经过一番搜索,我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的便捷存储过程将返回数据库使用的所有空间。如果提供了表名,则返回该表使用的空间。但是,存储过程返回的结果不可排序,因为列是字符值。

以下脚本将生成我正在寻找的信息。

create table #TableSize (
    Name varchar(255),
    [rows] int,
    reserved varchar(255),
    data varchar(255),
    index_size varchar(255),
    unused varchar(255))
create table #ConvertedSizes (
    Name varchar(255),
    [rows] int,
    reservedKb int,
    dataKb int,
    reservedIndexSize int,
    reservedUnused int)

EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows], 
SUBSTRING(reserved, 0, LEN(reserved)-2), 
SUBSTRING(data, 0, LEN(data)-2), 
SUBSTRING(index_size, 0, LEN(index_size)-2), 
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize

select * from #ConvertedSizes
order by reservedKb desc

drop table #TableSize
drop table #ConvertedSizes

答案 5 :(得分:31)

 exec  sp_spaceused N'dbo.MyTable'

对于所有表格,请使用..(从保罗的评论中添加)

exec sp_MSForEachTable 'exec sp_spaceused [?]'

答案 6 :(得分:20)

上面的查询很适合查找表使用的空间量(包括索引),但是如果要比较表上索引使用的空间量,请使用以下查询:

SELECT
    OBJECT_NAME(i.OBJECT_ID) AS TableName,
    i.name AS IndexName,
    i.index_id AS IndexID,
    8 * SUM(a.used_pages) AS 'Indexsize(KB)'
FROM
    sys.indexes AS i JOIN 
    sys.partitions AS p ON p.OBJECT_ID = i.OBJECT_ID AND p.index_id = i.index_id JOIN 
    sys.allocation_units AS a ON a.container_id = p.partition_id
where [i].[is_primary_key] = 0 -- fix for size discrepancy
GROUP BY
    i.OBJECT_ID,
    i.index_id,
    i.name
ORDER BY
    OBJECT_NAME(i.OBJECT_ID),
    i.index_id

答案 7 :(得分:13)

如果您需要计算SSMS中“表属性 - 存储”页面上完全相同的数字,则需要使用与SSMS中相同的方法对它们进行计数(适用于sql server 2005及更高版本。 。并且对于具有LOB字段的表也能正常工作 - 因为只计算“used_pa​​ges”不应该显示准确的索引大小):

;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
            WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
            ELSE lob_used_page_count + row_overflow_used_page_count
        END) as pages
FROM sys.dm_db_partition_stats  AS s 
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
    cte.TableName, 
    cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB, 
    cast(((CASE WHEN cte.used_pages_count > cte.pages 
                THEN cte.used_pages_count - cte.pages
                ELSE 0 
          END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc

答案 8 :(得分:9)

我们使用表分区,由于重复记录,上面提供的查询有些问题。

对于那些需要这个的人,您可以在SQL Server 2014运行的查询下面找到按表格生成&#34;磁盘使用情况&#34;报告。我认为它也适用于以前版本的SQL Server。

它就像一个魅力。

MySqlCommand

答案 9 :(得分:7)

扩展到@xav answer处理表分区以获得MB和GB的大小。 在SQL Server 2008/2012上进行了测试(在is_memory_optimized = 1

中注释了一行
SELECT
    a2.name AS TableName,
    a1.rows as [RowCount],
    --(a1.reserved + ISNULL(a4.reserved,0)) * 8 AS ReservedSize_KB,
    --a1.data * 8 AS DataSize_KB,
    --(CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS IndexSize_KB,
    --(CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS UnusedSize_KB,
    CAST(ROUND(((a1.reserved + ISNULL(a4.reserved,0)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS ReservedSize_MB,
    CAST(ROUND(a1.data * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS DataSize_MB,
    CAST(ROUND((CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS IndexSize_MB,
    CAST(ROUND((CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSize_MB,
    --'| |' Separator_MB_GB,
    CAST(ROUND(((a1.reserved + ISNULL(a4.reserved,0)) * 8) / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS ReservedSize_GB,
    CAST(ROUND(a1.data * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS DataSize_GB,
    CAST(ROUND((CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS IndexSize_GB,
    CAST(ROUND((CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSize_GB
FROM
    (SELECT 
        ps.object_id,
        SUM (CASE WHEN (ps.index_id < 2) THEN row_count ELSE 0 END) AS [rows],
        SUM (ps.reserved_page_count) AS reserved,
        SUM (CASE
                WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
                ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
            END
            ) AS data,
        SUM (ps.used_page_count) AS used
    FROM sys.dm_db_partition_stats ps
        --===Remove the following comment for SQL Server 2014+
        --WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
    GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN 
    (SELECT 
        it.parent_id,
        SUM(ps.reserved_page_count) AS reserved,
        SUM(ps.used_page_count) AS used
     FROM sys.dm_db_partition_stats ps
     INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
     WHERE it.internal_type IN (202,204)
     GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2  ON ( a1.object_id = a2.object_id ) 
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N'S' and a2.type <> N'IT'
--AND a2.name = 'MyTable'       --Filter for specific table
--ORDER BY a3.name, a2.name
ORDER BY ReservedSize_MB DESC

答案 10 :(得分:6)

-- Show the size of all the tables in a database sort by data size descending
SET NOCOUNT ON
DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE @cmd1 varchar(500)
SET @cmd1 = 'exec sp_spaceused ''?'''

INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable @command1=@cmd1

SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC

答案 11 :(得分:5)

Mar_c的回答有一个小小的改动,因为我经常回到这个页面,大多数是第一行的命令:

SELECT
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB,
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
    sys.tables t
INNER JOIN
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
    sys.schemas s ON t.schema_id = s.schema_id
WHERE
    t.NAME NOT LIKE 'dt%'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY
    t.Name, s.Name, p.Rows
ORDER BY
    --p.rows DESC --Uncomment to order by amount rows instead of size in KB.
    SUM(a.total_pages) DESC 

答案 12 :(得分:4)

这将为您提供每个表的大小和记录计数。

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
-- Get a list of tables and their sizes on disk
ALTER PROCEDURE [dbo].[sp_Table_Sizes]
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;
DECLARE @table_name VARCHAR(500)  
DECLARE @schema_name VARCHAR(500)  
DECLARE @tab1 TABLE( 
        tablename VARCHAR (500) collate database_default 
       ,schemaname VARCHAR(500) collate database_default 
) 

CREATE TABLE #temp_Table ( 
        tablename sysname 
       ,row_count INT 
       ,reserved VARCHAR(50) collate database_default 
       ,data VARCHAR(50) collate database_default 
       ,index_size VARCHAR(50) collate database_default 
       ,unused VARCHAR(50) collate database_default  
) 

INSERT INTO @tab1  
SELECT Table_Name, Table_Schema  
FROM information_schema.tables  
WHERE TABLE_TYPE = 'BASE TABLE' 

DECLARE c1 CURSOR FOR 
SELECT Table_Schema + '.' + Table_Name   
FROM information_schema.tables t1  
WHERE TABLE_TYPE = 'BASE TABLE' 

OPEN c1 
FETCH NEXT FROM c1 INTO @table_name 
WHILE @@FETCH_STATUS = 0  
BEGIN   
        SET @table_name = REPLACE(@table_name, '[','');  
        SET @table_name = REPLACE(@table_name, ']','');  

        -- make sure the object exists before calling sp_spacedused 
        IF EXISTS(SELECT id FROM sysobjects WHERE id = OBJECT_ID(@table_name)) 
        BEGIN 
               INSERT INTO #temp_Table EXEC sp_spaceused @table_name, false; 
        END 

        FETCH NEXT FROM c1 INTO @table_name 
END 
CLOSE c1 
DEALLOCATE c1 

SELECT  t1.* 
       ,t2.schemaname  
FROM #temp_Table t1  
INNER JOIN @tab1 t2 ON (t1.tablename = t2.tablename ) 
ORDER BY schemaname,t1.tablename; 

DROP TABLE #temp_Table
END

答案 13 :(得分:3)

要获取一个数据库中的所有表大小,您可以使用此查询:

Exec sys.sp_MSforeachtable ' sp_spaceused "?" '

您可以更改它以将所有结果插入到临时表中,然后从临时表中选择。

Insert into #TempTable Exec sys.sp_MSforeachtable ' sp_spaceused "?" ' 
Select * from #TempTable

答案 14 :(得分:2)

使用OSQL从命令提示符输入:

OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt

答案 15 :(得分:2)

以下是通过以下步骤快速获取所有表格大小的方法:

  1. 编写给定的 T-SQL命令以列出所有数据库表:

    select 'exec sp_spaceused ' + TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_TYPE = 'BASE TABLE'
    
  2. 现在复制数据库表列表,并将其复制到新的查询分析器窗口

    exec sp_spaceused table1
    exec sp_spaceused table2
    exec sp_spaceused table3
    exec sp_spaceused table4
    exec sp_spaceused table5
    
  3. 在SQL 查询分析器中,从顶部工具栏选项中选择结果到文件 Ctrl + Shift + F )。

  4. 现在最后点击上面工具栏标记的执行按钮红色。

  5. 数据库所有表格的大小现在存储在您计算机上的文件中。

    Enter image description here

答案 16 :(得分:2)

我在marc_s回答:

之上添加了几列
with fs
as
(
select i.object_id,
        p.rows AS RowCounts,
        SUM(a.total_pages) * 8 AS TotalSpaceKb
from     sys.indexes i INNER JOIN 
        sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id INNER JOIN 
         sys.allocation_units a ON p.partition_id = a.container_id
WHERE 
    i.OBJECT_ID > 255 
GROUP BY 
    i.object_id,
    p.rows
)

SELECT 
    t.NAME AS TableName,
    fs.RowCounts,
    fs.TotalSpaceKb,
    t.create_date,
    t.modify_date,
    ( select COUNT(1)
        from sys.columns c 
        where c.object_id = t.object_id ) TotalColumns    
FROM 
    sys.tables t INNER JOIN      
    fs  ON t.OBJECT_ID = fs.object_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
ORDER BY 
    t.Name

答案 17 :(得分:1)

作为对marc_s的答案(已被接受的答案)的简单扩展,将其调整为返回列数并允许过滤:

SELECT *
FROM
(

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    (SUM(a.used_pages) * 8) AS UsedSpaceKB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
    INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255
GROUP BY 
    t.Name, s.Name, p.Rows
) AS Result

WHERE
    RowCounts > 1000
    AND ColumnCount > 10
ORDER BY 
    UsedSpaceKB DESC

答案 18 :(得分:1)

我的帖子仅与SQL Server 2000相关,并且经过测试可在我的环境中使用。

此代码访问单个实例的所有可能数据库,而不仅仅是单个数据库。

我使用两个临时表来帮助收集适当的数据,然后将结果转储到一个“实时”表中。

返回的数据是:DatabaseName,DatabaseTableName,Rows(在表中),数据(表中KB的大小),条目数据(我发现这对于了解我上次运行脚本的时间非常有用)。

此代码的垮掉是'data'字段没有存储为int(字符'KB'保存在该字段中),这对于排序很有用(但不是完全必要的)。

希望这段代码可以帮助那些人并节省一些时间!

CREATE PROCEDURE [dbo].[usp_getAllDBTableSizes]

AS
BEGIN
   SET NOCOUNT OFF

   CREATE TABLE #DatabaseTables([dbname] sysname,TableName sysname)
   CREATE TABLE #AllDatabaseTableSizes(Name sysname,[rows] VARCHAR(18), reserved VARCHAR(18), data VARCHAR(18), index_size VARCHAR(18), unused VARCHAR(18))

   DECLARE @SQL nvarchar(4000)
   SET @SQL='select ''?'' AS [Database], Table_Name from [?].information_schema.tables WHERE TABLE_TYPE = ''BASE TABLE'' '

   INSERT INTO #DatabaseTables(DbName, TableName)
      EXECUTE sp_msforeachdb @Command1=@SQL

   DECLARE AllDatabaseTables CURSOR LOCAL READ_ONLY FOR   
   SELECT TableName FROM #DatabaseTables

   DECLARE AllDatabaseNames CURSOR LOCAL READ_ONLY FOR   
   SELECT DBName FROM #DatabaseTables

   DECLARE @DBName sysname  
   OPEN AllDatabaseNames  

   DECLARE @TName sysname
   OPEN AllDatabaseTables  

   WHILE 1=1 BEGIN 
      FETCH NEXT FROM AllDatabaseNames INTO @DBName  
      FETCH NEXT FROM AllDatabaseTables INTO @TName 
      IF @@FETCH_STATUS<>0 BREAK  
      INSERT INTO #AllDatabaseTableSizes
         EXEC ( 'EXEC ' + @DBName + '.dbo.sp_spaceused ' + @TName) 

   END 

   --http://msdn.microsoft.com/en-us/library/aa175920(v=sql.80).aspx
   INSERT INTO rsp_DatabaseTableSizes (DatabaseName, name, [rows], data)
      SELECT   [dbname], name, [rows],  data FROM #DatabaseTables
      INNER JOIN #AllDatabaseTableSizes
      ON #DatabaseTables.TableName = #AllDatabaseTableSizes.Name
      GROUP BY [dbname] , name, [rows],  data
      ORDER BY [dbname]
   --To be honest, I have no idea what exact duplicates we are dropping
    -- but in my case a near enough approach has been good enough.
   DELETE FROM [rsp_DatabaseTableSizes]
   WHERE name IN 
      ( 
      SELECT name 
      FROM [rsp_DatabaseTableSizes]
      GROUP BY name
      HAVING COUNT(*) > 1
      )

   DROP TABLE #DatabaseTables
   DROP TABLE #AllDatabaseTableSizes

   CLOSE AllDatabaseTables  
   DEALLOCATE AllDatabaseTables  

   CLOSE AllDatabaseNames  
   DEALLOCATE AllDatabaseNames      
END

--EXEC [dbo].[usp_getAllDBTableSizes] 

如果您需要知道, rsp_DatabaseTableSizes 表是通过以下方式创建的:

CREATE TABLE [dbo].[rsp_DatabaseSizes](
    [DatabaseName] [varchar](1000) NULL,
    [dbSize] [decimal](15, 2) NULL,
    [DateUpdated] [smalldatetime] NULL
) ON [PRIMARY]

GO

答案 19 :(得分:1)

如果您只关心数据库中的空白空间而不是单个表,则可以考虑以下内容:

如果数据库经历了大量的数据插入然后删除的操作(例如在ETL情况下),这将导致数据库中文件组自动增长,但是从不自动扩展,从而导致数据库中的未使用空间过多-收缩。

通过使用数据库的属性页面,可以查看是否是这种情况。您可以缩小(右键单击数据库>任务>缩小)并收回一些空间。但是,如果根本原因仍然存在,数据库将重新增长(并花费额外的时间尝试重新增长,并且事情变慢,直到增长足够,因此在这种情况下不要这样做)

(KEK: key encryption key)

答案 20 :(得分:1)

当前接受的答案具有2600多个投票,但在使用多个分区和/或过滤索引时会给出错误结果。它还不能区分数据大小和索引大小,这通常是非常相关的。一些建议的修复程序无法解决核心问题,或者根本就是错误的。

以下查询解决了所有这些问题。

SELECT 
     [object_id]        = t.[object_id]
    ,[schema_name]      = s.[name]
    ,[table_name]       = t.[name]
    ,[index_name]       = CASE WHEN i.[type] in (0,1,5) THEN null    ELSE i.[name] END -- 0=Heap; 1=Clustered; 5=Clustered Columnstore
    ,[object_type]      = CASE WHEN i.[type] in (0,1,5) THEN 'TABLE' ELSE 'INDEX'  END
    ,[index_type]       = i.[type_desc]
    ,[partition_count]  = p.partition_count
    ,[row_count]        = p.[rows]
    ,[data_compression] = CASE WHEN p.data_compression_cnt > 1 THEN 'Mixed'
                               ELSE (  SELECT DISTINCT p.data_compression_desc
                                       FROM sys.partitions p
                                       WHERE i.[object_id] = p.[object_id] AND i.index_id = p.index_id
                                    )
                          END
    ,[total_space_MB]   = cast(round(( au.total_pages                  * (8/1024.00)), 2) AS DECIMAL(36,2))
    ,[used_space_MB]    = cast(round(( au.used_pages                   * (8/1024.00)), 2) AS DECIMAL(36,2))
    ,[unused_space_MB]  = cast(round(((au.total_pages - au.used_pages) * (8/1024.00)), 2) AS DECIMAL(36,2))
FROM sys.schemas s
JOIN sys.tables  t ON s.schema_id = t.schema_id
JOIN sys.indexes i ON t.object_id = i.object_id
JOIN (
    SELECT [object_id], index_id, partition_count=count(*), [rows]=sum([rows]), data_compression_cnt=count(distinct [data_compression])
    FROM sys.partitions
    GROUP BY [object_id], [index_id]
) p ON i.[object_id] = p.[object_id] AND i.[index_id] = p.[index_id]
JOIN (
    SELECT p.[object_id], p.[index_id], total_pages = sum(a.total_pages), used_pages = sum(a.used_pages), data_pages=sum(a.data_pages)
    FROM sys.partitions p
    JOIN sys.allocation_units a ON p.[partition_id] = a.[container_id]
    GROUP BY p.[object_id], p.[index_id]
) au ON i.[object_id] = au.[object_id] AND i.[index_id] = au.[index_id]
WHERE t.is_ms_shipped = 0 -- Not a system table

答案 21 :(得分:0)

重复上面的@Mark回答,添加了@ updateusage ='true'来强制使用最新尺寸统计信息(https://msdn.microsoft.com/en-us/library/ms188776.aspx):

        SET NOCOUNT ON
        DECLARE @TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
        DECLARE @cmd1 varchar(500)
        SET @cmd1 = 'exec sp_spaceused @objname =''?'', @updateusage =''true'' '

        INSERT INTO @TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
        EXEC sp_msforeachtable @command1=@cmd1 
SELECT * FROM @TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC

答案 22 :(得分:0)

这是一个示例查询,用于获取按大小降序排列的大于1GB的表。

USE YourDB
GO

DECLARE @Mult float = 8
SET @Mult = @Mult / POWER(2, 20) -- Use POWER(2, 10) for MBs

; WITH CTE AS
(
SELECT
    i.object_id,
    Rows = MAX(p.rows),
    TotalSpaceGB = ROUND(SUM(a.total_pages) * @Mult, 0),
    UsedSpaceGB = ROUND(SUM(a.used_pages) * @Mult, 0)
FROM 
    sys.indexes i
JOIN
    sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
JOIN
    sys.allocation_units a ON p.partition_id = a.container_id
WHERE
    i.object_id > 255
GROUP BY
    i.object_id
HAVING
    SUM(a.total_pages) * @Mult > 1
)
SELECT 
    SchemaName = s.name,
    TableName = t.name,
    c.TotalSpaceGB,
    c.UsedSpaceGB,
    UnusedSpaceGB = c.TotalSpaceGB - c.UsedSpaceGB,
    [RowCount] = c.Rows
FROM 
    CTE c
JOIN    
    sys.tables t ON t.object_id = c.object_id
JOIN
    sys.schemas s ON t.schema_id = s.schema_id
ORDER BY
    c.TotalSpaceGB DESC

答案 23 :(得分:0)

对于Azure,我使用了以下方法:

您应该拥有SSMS v17.x

我曾经用过

enter image description here

以此作为用户Sparrow has mentioned

打开您的Databases>并选择表格
然后按 F7 键 您应该看到row count
为: enter image description here

SSMS 此处已连接到Azure数据库

答案 24 :(得分:0)

我发现此查询易于使用且快速。

select schema_name(tab.schema_id) + '.' + tab.name as [table], 
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind 
    on tab.object_id = ind.object_id
inner join sys.partitions  (nolock) part 
    on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
    on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc
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