Question

我有这个查询（如下所示）目前使用临时文件和，以便按一组有序结果生成一组。如果可能的话，我想摆脱它们的使用。我已经查看了此查询中使用的基础索引，但我看不到缺少的内容。

SELECT 
  b.institutionid AS b__institutionid,
  b.name AS b__name,  
  COUNT(DISTINCT f2.facebook_id) AS f2__0 
FROM education_institutions b 
LEFT JOIN facebook_education_matches f ON b.institutionid = f.institutionid 
LEFT JOIN facebook_education f2 ON f.school_uid = f2.school_uid 
WHERE 
  (
  b.approved = '1' 
  AND f2.facebook_id IN ( [lots of facebook ids here ])
  ) 
GROUP BY b__institutionid 
ORDER BY f2__0 DESC
LIMIT 10

以下是EXPLAIN EXTENDED的输出：

+----+-------------+-------+--------+--------------------------------+----------------+---------+----------------------------------+------+----------+----------------------------------------------+
| id | select_type | table | type   | possible_keys                  | key            | key_len | ref                              | rows | filtered | Extra                                        |
+----+-------------+-------+--------+--------------------------------+----------------+---------+----------------------------------+------+----------+----------------------------------------------+
|  1 | SIMPLE      | f     | index  | PRIMARY,institutionId          | institutionId  | 4       | NULL                             |  308 |   100.00 | Using index; Using temporary; Using filesort |
|  1 | SIMPLE      | f2    | ref    | facebook_id_idx,school_uid_idx | school_uid_idx | 9       | f.school_uid                     |    1 |   100.00 | Using where                                  |
|  1 | SIMPLE      | b     | eq_ref | PRIMARY                        | PRIMARY        | 4       | f.institutionId                  |    1 |   100.00 | Using where                                  |
+----+-------------+-------+--------+--------------------------------+----------------+---------+----------------------------------+------+----------+----------------------------------------------+

每个表的CREATE TABLE语句如下所示，因此您了解架构。

CREATE TABLE facebook_education (
  education_id int(11) NOT NULL AUTO_INCREMENT,
  name varchar(255) DEFAULT NULL,
  school_uid bigint(20) DEFAULT NULL,
  school_type varchar(255) DEFAULT NULL,
  year smallint(6) DEFAULT NULL,
  facebook_id bigint(20) DEFAULT NULL,
  degree varchar(255) DEFAULT NULL,
  PRIMARY KEY (education_id),
  KEY facebook_id_idx (facebook_id),
  KEY school_uid_idx (school_uid),
  CONSTRAINT facebook_education_facebook_id_facebook_user_facebook_id FOREIGN KEY (facebook_id) REFERENCES facebook_user (facebook_id)
) ENGINE=InnoDB AUTO_INCREMENT=484 DEFAULT CHARSET=utf8;

CREATE TABLE facebook_education_matches (
  school_uid bigint(20) NOT NULL,
  institutionId int(11) NOT NULL,
  created_at timestamp NULL DEFAULT NULL,
  updated_at timestamp NULL DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP,
  PRIMARY KEY (school_uid),
  KEY institutionId (institutionId),
  CONSTRAINT fk_facebook_education FOREIGN KEY (school_uid) REFERENCES facebook_education (school_uid) ON DELETE CASCADE ON UPDATE CASCADE,
  CONSTRAINT fk_education_institutions FOREIGN KEY (institutionId) REFERENCES education_institutions (institutionId) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT;

CREATE TABLE education_institutions (
  institutionId int(11) NOT NULL AUTO_INCREMENT,
  name varchar(100) NOT NULL,
  type enum('School','Degree') DEFAULT NULL,
  approved tinyint(1) NOT NULL DEFAULT '0',
  deleted tinyint(1) NOT NULL DEFAULT '0',
  normalisedName varchar(100) NOT NULL,
  created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  PRIMARY KEY (institutionId)
) ENGINE=InnoDB AUTO_INCREMENT=101327 DEFAULT CHARSET=utf8;

非常感谢任何指导。

Answer 1

文件排序可能是因为您没有合适的ORDER BY索引

在MySQL "ORDER BY Optimization"文档中提到过。

您可以做的是加载临时表，然后从中进行选择。加载临时表时，请使用ORDER BY NULL。从临时表中选择时，请使用ORDER BY .. LIMIT

问题是group by添加了隐式order by <group by clause> ASC，除非您通过添加order by null来禁用该行为。
这是MySQL具体的问题之一。

Answer 2

我可以看到两种可能的优化，

b.approved ='1' - 您肯定需要批准列上的索引才能快速过滤。
f2.facebook_id IN（[这里有很多facebook ids]）） - 将facebook ID存储在临时表中。然后在临时表上创建一个索引，然后与临时表连接，而不是使用IN子句。

使用临时和filesort优化MySql查询

2 个答案: